What are the solutions to the equation 2x^2+9x=0 ?

The solutions to the equation 2x^2+9x=0 are x=0,x=-9/2

Find the zeros of 2x^2+9x=0

The zeros of 2x^2+9x=0 are x=0,x=-9/2

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2 x^{2} + 9 x = 0

x = 0, x = - \frac{9}{2}

Decimal Notation

x = 0, x = - 4.5

Solution steps

2 x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 \cdot 2}, x_{2} = \frac{- 9 - 9}{2 \cdot 2}

x = \frac{- 9 + 9}{2 \cdot 2} : 0

x = \frac{- 9 - 9}{2 \cdot 2} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{9}{2}

5 x^{2} + 9 x - 18 = 0

\frac{π}{8} \cdot 2

\frac{12 !}{5 ! ( 12 - 5 ) !}

- 2 + 2 x = - 7 x - 74

\frac{8 π}{3} - 2 π

What are the solutions to the equation 2x^2+9x=0 ?
The solutions to the equation 2x^2+9x=0 are x=0,x=-9/2
Find the zeros of 2x^2+9x=0
The zeros of 2x^2+9x=0 are x=0,x=-9/2