What are the solutions to the equation 5x^2+9x-18=0 ?

The solutions to the equation 5x^2+9x-18=0 are x= 6/5 ,x=-3

Find the zeros of 5x^2+9x-18=0

The zeros of 5x^2+9x-18=0 are x= 6/5 ,x=-3

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5 x^{2} + 9 x - 18 = 0

x = \frac{6}{5}, x = - 3

Decimal Notation

x = 1.2, x = - 3

Solution steps

5 x^{2} + 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 18 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 18) = 21

x_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 21}{2 \cdot 5}, x_{2} = \frac{- 9 - 21}{2 \cdot 5}

x = \frac{- 9 + 21}{2 \cdot 5} : \frac{6}{5}

x = \frac{- 9 - 21}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = - 3

\frac{π}{8} \cdot 2

\frac{12 !}{5 ! ( 12 - 5 ) !}

- 2 + 2 x = - 7 x - 74

\frac{8 π}{3} - 2 π

x - 4 = 5 x + 8

What are the solutions to the equation 5x^2+9x-18=0 ?
The solutions to the equation 5x^2+9x-18=0 are x= 6/5 ,x=-3
Find the zeros of 5x^2+9x-18=0
The zeros of 5x^2+9x-18=0 are x= 6/5 ,x=-3