What are the solutions to the equation x^2+9x-5=0 ?

The solutions to the equation x^2+9x-5=0 are x=(-9+sqrt(101))/2 ,x=(-9-sqrt(101))/2

Find the zeros of x^2+9x-5=0

The zeros of x^2+9x-5=0 are x=(-9+sqrt(101))/2 ,x=(-9-sqrt(101))/2

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x^{2} + 9 x - 5 = 0

x = \frac{- 9 + 101}{2}, x = \frac{- 9 - 101}{2}

Decimal Notation

x = 0.52493 \dots, x = - 9.52493 \dots

Solution steps

x^{2} + 9 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 5) = 101

x_{1, 2} = \frac{- 9 \pm 101}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 101}{2 \cdot 1}, x_{2} = \frac{- 9 - 101}{2 \cdot 1}

x = \frac{- 9 + 101}{2 \cdot 1} : \frac{- 9 + 101}{2}

x = \frac{- 9 - 101}{2 \cdot 1} : \frac{- 9 - 101}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 101}{2}, x = \frac{- 9 - 101}{2}

- a^{2} + 3 a + 4

x^{2} + (\frac{2}{3})^{2} = 1

9 y^{4} - 27 y

3 (x + 2) > 15

5 x - 19 + 2 x + 10 = 180

What are the solutions to the equation x^2+9x-5=0 ?
The solutions to the equation x^2+9x-5=0 are x=(-9+sqrt(101))/2 ,x=(-9-sqrt(101))/2
Find the zeros of x^2+9x-5=0
The zeros of x^2+9x-5=0 are x=(-9+sqrt(101))/2 ,x=(-9-sqrt(101))/2