What are the solutions to the equation x^2+((sqrt(2))/3)^2=1 ?

The solutions to the equation x^2+((sqrt(2))/3)^2=1 are x=(sqrt(7))/3 ,x=-(sqrt(7))/3

Find the zeros of x^2+((sqrt(2))/3)^2=1

The zeros of x^2+((sqrt(2))/3)^2=1 are x=(sqrt(7))/3 ,x=-(sqrt(7))/3

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x^{2} + (\frac{2}{3})^{2} = 1

x = \frac{7}{3}, x = - \frac{7}{3}

Decimal Notation

x = 0.88191 \dots, x = - 0.88191 \dots

Solution steps

x^{2} + (\frac{2}{3})^{2} = 1

Expand

x^{2} + (\frac{2}{3})^{2} : x^{2} + \frac{2}{9}

x^{2} + \frac{2}{9} = 1

Move

\frac{2}{9}

to the right side

x^{2} = 1 - \frac{2}{9}

Simplify

1 - \frac{2}{9} : \frac{7}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{9}, x = - \frac{7}{9}

\frac{7}{9} = \frac{7}{3}

- \frac{7}{9} = - \frac{7}{3}

x = \frac{7}{3}, x = - \frac{7}{3}

9 y^{4} - 27 y

3 (x + 2) > 15

5 x - 19 + 2 x + 10 = 180

6 x^{2} - 16 x + 8 = 0

\frac{7 !}{3 !}

What are the solutions to the equation x^2+((sqrt(2))/3)^2=1 ?
The solutions to the equation x^2+((sqrt(2))/3)^2=1 are x=(sqrt(7))/3 ,x=-(sqrt(7))/3
Find the zeros of x^2+((sqrt(2))/3)^2=1
The zeros of x^2+((sqrt(2))/3)^2=1 are x=(sqrt(7))/3 ,x=-(sqrt(7))/3