What are the solutions to the equation x^2+14x+65=0 ?

The solutions to the equation x^2+14x+65=0 are x=-7+4i,x=-7-4i

Find the zeros of x^2+14x+65=0

The zeros of x^2+14x+65=0 are x=-7+4i,x=-7-4i

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x^{2} + 14 x + 65 = 0

x = - 7 + 4 i, x = - 7 - 4 i

Solution steps

x^{2} + 14 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot 65 : 8 i

x_{1, 2} = \frac{- 14 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 14 - 8 i}{2 \cdot 1}

x = \frac{- 14 + 8 i}{2 \cdot 1} : - 7 + 4 i

x = \frac{- 14 - 8 i}{2 \cdot 1} : - 7 - 4 i

The solutions to the quadratic equation are:

x = - 7 + 4 i, x = - 7 - 4 i

(\frac{3}{4} - \frac{5}{2})^{2} - (\frac{3}{4})^{2}

10 0^{- \frac{3}{2}}

2 (x - 1)^{2} + 7 = 39

(x - 7)^{2} + 4 = 0

- 4 x - 32 < 4

What are the solutions to the equation x^2+14x+65=0 ?
The solutions to the equation x^2+14x+65=0 are x=-7+4i,x=-7-4i
Find the zeros of x^2+14x+65=0
The zeros of x^2+14x+65=0 are x=-7+4i,x=-7-4i