What are the solutions to the equation (x-7)^2+4=0 ?

The solutions to the equation (x-7)^2+4=0 are x=2i+7,x=-2i+7

Find the zeros of (x-7)^2+4=0

The zeros of (x-7)^2+4=0 are x=2i+7,x=-2i+7

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(x - 7)^{2} + 4 = 0

x = 2 i + 7, x = - 2 i + 7

Solution steps

(x - 7)^{2} + 4 = 0

Move

4

to the right side

(x - 7)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = - 4 : x = 2 i + 7

Solve

x - 7 = - - 4 : x = - 2 i + 7

The solutions to the quadratic equation are:

x = 2 i + 7, x = - 2 i + 7

- 4 x - 32 < 4

∣ x - 2 ∣ < 7

x^{2} + 6 x + 5 = 0

- 4 x + 9 \leq - 3 x + 2

What are the solutions to the equation (x-7)^2+4=0 ?
The solutions to the equation (x-7)^2+4=0 are x=2i+7,x=-2i+7
Find the zeros of (x-7)^2+4=0
The zeros of (x-7)^2+4=0 are x=2i+7,x=-2i+7