What are the solutions to the equation 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0 ?

The solutions to the equation 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0 are p= 1/2 ,p=-4

Find the zeros of 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0

The zeros of 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0 are p= 1/2 ,p=-4

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3 p^{3} + (p + 3) p^{2} + (7 - p - 4 p^{2}) p - 4 = 0

p = \frac{1}{2}, p = - 4

Decimal Notation

p = 0.5, p = - 4

Solution steps

3 p^{3} + (p + 3) p^{2} + (7 - p - 4 p^{2}) p - 4 = 0

Expand

3 p^{3} + (p + 3) p^{2} + (7 - p - 4 p^{2}) p - 4 : 2 p^{2} + 7 p - 4

2 p^{2} + 7 p - 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 4) = 9

p_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 7 + 9}{2 \cdot 2}, p_{2} = \frac{- 7 - 9}{2 \cdot 2}

p = \frac{- 7 + 9}{2 \cdot 2} : \frac{1}{2}

p = \frac{- 7 - 9}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

p = \frac{1}{2}, p = - 4

2 (7 + 5)^{2}

\frac{2 n}{6 n + 4} \cdot \frac{3 n + 2}{3 n - 2}

28 = 4 \cdot (7 - x)

- 3 (3 x - 5) = 6 x

(x + 5) (x - 1) = 0

What are the solutions to the equation 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0 ?
The solutions to the equation 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0 are p= 1/2 ,p=-4
Find the zeros of 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0
The zeros of 3p^3+(p+3)p^2+(7-p-4p^2)p-4=0 are p= 1/2 ,p=-4