What are the solutions to the equation (x+5)(x-1)=0 ?

The solutions to the equation (x+5)(x-1)=0 are x=-5,x=1

Find the zeros of (x+5)(x-1)=0

The zeros of (x+5)(x-1)=0 are x=-5,x=1

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(x + 5) (x - 1) = 0

x = - 5, x = 1

Solution steps

(x + 5) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x - 1 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - 5, x = 1

\frac{6 m ^{2} - 5 m y - y ^{2}}{12 m + 2 y}

x^{2} - 19 x + 90

3 \cdot x^{2} - 9 = 0

704

- \frac{2}{3} (x - 5) = \frac{3}{2} (x + 1)

What are the solutions to the equation (x+5)(x-1)=0 ?
The solutions to the equation (x+5)(x-1)=0 are x=-5,x=1
Find the zeros of (x+5)(x-1)=0
The zeros of (x+5)(x-1)=0 are x=-5,x=1