What are the solutions to the equation 2x^2+2=12 ?

The solutions to the equation 2x^2+2=12 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 2x^2+2=12

The zeros of 2x^2+2=12 are x=sqrt(5),x=-sqrt(5)

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2 x^{2} + 2 = 12

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

2 x^{2} + 2 = 12

Move

2

to the right side

2 x^{2} = 10

Divide both sides by

2

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

35

4 x^{2} - 12 x = - 5

\frac{2 ^{2} y ^{- 6}}{8 ^{- 1} z ^{0} x ^{- 7}}

\frac{2 π}{10}

(2 x + 14)^{2} = 16

What are the solutions to the equation 2x^2+2=12 ?
The solutions to the equation 2x^2+2=12 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 2x^2+2=12
The zeros of 2x^2+2=12 are x=sqrt(5),x=-sqrt(5)