What are the solutions to the equation 4x^2-12x=-5 ?

The solutions to the equation 4x^2-12x=-5 are x= 5/2 ,x= 1/2

Find the zeros of 4x^2-12x=-5

The zeros of 4x^2-12x=-5 are x= 5/2 ,x= 1/2

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4 x^{2} - 12 x = - 5

x = \frac{5}{2}, x = \frac{1}{2}

Decimal Notation

x = 2.5, x = 0.5

Solution steps

4 x^{2} - 12 x = - 5

Move

5

to the left side

4 x^{2} - 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 5 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 4}

x = \frac{- ( - 12 ) + 8}{2 \cdot 4} : \frac{5}{2}

x = \frac{- ( - 12 ) - 8}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{2}

\frac{2 ^{2} y ^{- 6}}{8 ^{- 1} z ^{0} x ^{- 7}}

\frac{2 π}{10}

(2 x + 14)^{2} = 16

w^{2} + 12 w + 27

∣ 125 - u ∣ \leq 30

What are the solutions to the equation 4x^2-12x=-5 ?
The solutions to the equation 4x^2-12x=-5 are x= 5/2 ,x= 1/2
Find the zeros of 4x^2-12x=-5
The zeros of 4x^2-12x=-5 are x= 5/2 ,x= 1/2