What are the solutions to the equation 4x^2+12x-27=0 ?

The solutions to the equation 4x^2+12x-27=0 are x= 3/2 ,x=-9/2

Find the zeros of 4x^2+12x-27=0

The zeros of 4x^2+12x-27=0 are x= 3/2 ,x=-9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 12 x - 27 = 0

x = \frac{3}{2}, x = - \frac{9}{2}

Decimal Notation

x = 1.5, x = - 4.5

Solution steps

4 x^{2} + 12 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 27 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 27) = 24

x_{1, 2} = \frac{- 12 \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 24}{2 \cdot 4}, x_{2} = \frac{- 12 - 24}{2 \cdot 4}

x = \frac{- 12 + 24}{2 \cdot 4} : \frac{3}{2}

x = \frac{- 12 - 24}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{9}{2}

4^{\frac{1}{4}}

9 y^{2} + 25 = - 30 y

(x^{2} - 3) = 0

\frac{11 !}{7 !}

4 x^{2} - 15 x - 1 = 0

What are the solutions to the equation 4x^2+12x-27=0 ?
The solutions to the equation 4x^2+12x-27=0 are x= 3/2 ,x=-9/2
Find the zeros of 4x^2+12x-27=0
The zeros of 4x^2+12x-27=0 are x= 3/2 ,x=-9/2