What are the solutions to the equation 9y^2+25=-30y ?

The solutions to the equation 9y^2+25=-30y are y=-5/3

Find the zeros of 9y^2+25=-30y

The zeros of 9y^2+25=-30y are y=-5/3

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9 y^{2} + 25 = - 30 y

y = - \frac{5}{3}

Decimal Notation

y = - 1.66666 \dots

Solution steps

9 y^{2} + 25 = - 30 y

Move

30 y

to the left side

9 y^{2} + 25 + 30 y = 0

Write in the standard form

a x^{2} + b x + c = 0

9 y^{2} + 30 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 9 \cdot 25}{2 \cdot 9}

3 0^{2} - 4 \cdot 9 \cdot 25 = 0

y_{1, 2} = \frac{- 30 \pm 0}{2 \cdot 9}

y = \frac{- 30}{2 \cdot 9}

\frac{- 30}{2 \cdot 9} = - \frac{5}{3}

y = - \frac{5}{3}

The solution to the quadratic equation is:

y = - \frac{5}{3}

(x^{2} - 3) = 0

\frac{11 !}{7 !}

4 x^{2} - 15 x - 1 = 0

∣ 3 x + 2 ∣ = ∣ 2 x + 23 ∣

7 (3 - 2 x) + 2 (2 x - 15) < 2 (5 x - 7) - 3 (2 x - 11)

What are the solutions to the equation 9y^2+25=-30y ?
The solutions to the equation 9y^2+25=-30y are y=-5/3
Find the zeros of 9y^2+25=-30y
The zeros of 9y^2+25=-30y are y=-5/3