Two cyclists leave towns 156 kilometers apart at the same time and travel toward each other. One cyclist travels 3kph slower than the other. If they meet in 4 hours, what is the rate of each cyclist?

الحلّ

الحلّ

first cyclis t^{'} s speed : 18

second cyclis t^{'} s speed : 21

خطوات الحلّ

Translate the problem into an equation:

x \cdot 4 + (x + 3) \cdot 4 = 156

x \cdot 4 + (x + 3) \cdot 4 = 156, x

حلّ لـ:

x = 18

speed جد

first cyclis t^{'} s speed : 18

second cyclis t^{'} s speed : 21

أمثلة شائعة

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