What is the value of sin(2pii) ?

The value of sin(2pii) is i(-1+e^{4pi})/(2e^{2pi)}

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Popular >

sin(2pii)

Solution

sin (2 πi)

Solution

i \frac{- 1 + e ^{4 π}}{2 e ^{2 π}}

Solution steps

sin (2 πi)

Rewrite using trig identities:

sin (0) cosh (2 π) + i cos (0) sinh (2 π)

sin (2 πi)

Use the following identity:

sin (a + bi) = sin (a) cosh (b) + i cos (a) sinh (b)

= sin (0) cosh (2 π) + i cos (0) sinh (2 π)

= sin (0) cosh (2 π) + i cos (0) sinh (2 π)

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Rewrite using trig identities:

cosh (2 π) = \frac{e ^{4 π} + 1}{2 e ^{2 π}}

cosh (2 π)

Use the Hyperbolic identity:

cosh (x) = \frac{e ^{x} + e ^{- x}}{2}

= \frac{e ^{2 π} + e ^{- 2 π}}{2}

\frac{e ^{2 π} + e ^{- 2 π}}{2} = \frac{e ^{4 π} + 1}{2 e ^{2 π}}

\frac{e ^{2 π} + e ^{- 2 π}}{2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{e ^{2 π} + \frac{1}{e ^{2 π}}}{2}

Join

e^{2 π} + \frac{1}{e ^{2 π}} : \frac{e ^{4 π} + 1}{e ^{2 π}}

e^{2 π} + \frac{1}{e ^{2 π}}

Convert element to fraction:

e^{2 π} = \frac{e ^{2 π} e ^{2 π}}{e ^{2 π}}

= \frac{e ^{2 π} e ^{2 π}}{e ^{2 π}} + \frac{1}{e ^{2 π}}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{2 π} e ^{2 π} + 1}{e ^{2 π}}

e^{2 π} e^{2 π} + 1 = e^{4 π} + 1

e^{2 π} e^{2 π} + 1

e^{2 π} e^{2 π} = e^{4 π}

e^{2 π} e^{2 π}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{2 π} e^{2 π} = e^{2 π + 2 π}

= e^{2 π + 2 π}

Add similar elements:

2 π + 2 π = 4 π

= e^{4 π}

= e^{4 π} + 1

= \frac{e ^{4 π} + 1}{e ^{2 π}}

= \frac{\frac{e ^{4 π} + 1}{e ^{2 π}}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{e ^{4 π} + 1}{e ^{2 π} \cdot 2}

= \frac{e ^{4 π} + 1}{2 e ^{2 π}}

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

Rewrite using trig identities:

sinh (2 π) = \frac{e ^{4 π} - 1}{2 e ^{2 π}}

sinh (2 π)

Use the Hyperbolic identity:

sinh (x) = \frac{e ^{x} - e ^{- x}}{2}

= \frac{e ^{2 π} - e ^{- 2 π}}{2}

\frac{e ^{2 π} - e ^{- 2 π}}{2} = \frac{e ^{4 π} - 1}{2 e ^{2 π}}

\frac{e ^{2 π} - e ^{- 2 π}}{2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{e ^{2 π} - \frac{1}{e ^{2 π}}}{2}

Join

e^{2 π} - \frac{1}{e ^{2 π}} : \frac{e ^{4 π} - 1}{e ^{2 π}}

e^{2 π} - \frac{1}{e ^{2 π}}

Convert element to fraction:

e^{2 π} = \frac{e ^{2 π} e ^{2 π}}{e ^{2 π}}

= \frac{e ^{2 π} e ^{2 π}}{e ^{2 π}} - \frac{1}{e ^{2 π}}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{2 π} e ^{2 π} - 1}{e ^{2 π}}

e^{2 π} e^{2 π} - 1 = e^{4 π} - 1

e^{2 π} e^{2 π} - 1

e^{2 π} e^{2 π} = e^{4 π}

e^{2 π} e^{2 π}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{2 π} e^{2 π} = e^{2 π + 2 π}

= e^{2 π + 2 π}

Add similar elements:

2 π + 2 π = 4 π

= e^{4 π}

= e^{4 π} - 1

= \frac{e ^{4 π} - 1}{e ^{2 π}}

= \frac{\frac{e ^{4 π} - 1}{e ^{2 π}}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{e ^{4 π} - 1}{e ^{2 π} \cdot 2}

= \frac{e ^{4 π} - 1}{2 e ^{2 π}}

= 0 \cdot \frac{e ^{4 π} + 1}{2 e ^{2 π}} + i 1 \cdot \frac{e ^{4 π} - 1}{2 e ^{2 π}}

Simplify

0 \cdot \frac{e ^{4 π} + 1}{2 e ^{2 π}} + i 1 \cdot \frac{e ^{4 π} - 1}{2 e ^{2 π}} : i \frac{- 1 + e ^{4 π}}{2 e ^{2 π}}

0 \cdot \frac{e ^{4 π} + 1}{2 e ^{2 π}} + i 1 \cdot \frac{e ^{4 π} - 1}{2 e ^{2 π}}

0 \cdot \frac{e ^{4 π} + 1}{2 e ^{2 π}} = 0

0 \cdot \frac{e ^{4 π} + 1}{2 e ^{2 π}}

Apply rule

0 \cdot a = 0

= 0

i 1 \cdot \frac{e ^{4 π} - 1}{2 e ^{2 π}} = \frac{i ( e ^{4 π} - 1 )}{2 e ^{2 π}}

i 1 \cdot \frac{e ^{4 π} - 1}{2 e ^{2 π}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 1 \cdot \frac{i ( e ^{4 π} - 1 )}{2 e ^{2 π}}

Multiply:

1 \cdot \frac{( e ^{4 π} - 1 ) i}{2 e ^{2 π}} = \frac{( e ^{4 π} - 1 ) i}{2 e ^{2 π}}

= \frac{i ( e ^{4 π} - 1 )}{2 e ^{2 π}}

= 0 + \frac{i ( e ^{4 π} - 1 )}{2 e ^{2 π}}

0 + \frac{( e ^{4 π} - 1 ) i}{2 e ^{2 π}} = \frac{( e ^{4 π} - 1 ) i}{2 e ^{2 π}}

= \frac{i ( e ^{4 π} - 1 )}{2 e ^{2 π}}

Rewrite

\frac{i ( e ^{4 π} - 1 )}{2 e ^{2 π}}

in standard complex form:

\frac{e ^{4 π} - 1}{2 e ^{2 π}} i

\frac{i ( e ^{4 π} - 1 )}{2 e ^{2 π}}

Expand

i (e^{4 π} - 1) : i e^{4 π} - i

i (e^{4 π} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = i, b = e^{4 π}, c = 1

= i e^{4 π} - i 1

= i e^{4 π} - 1 i

Multiply:

1 i = i

= i e^{4 π} - i

= \frac{i e ^{4 π} - i}{2 e ^{2 π}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{i e ^{4 π} - i}{2 e ^{2 π}} = \frac{i e ^{4 π}}{2 e ^{2 π}} - \frac{i}{2 e ^{2 π}}

= \frac{i e ^{4 π}}{2 e ^{2 π}} - \frac{i}{2 e ^{2 π}}

Cancel

\frac{i e ^{4 π}}{2 e ^{2 π}} : \frac{i e ^{2 π}}{2}

\frac{i e ^{4 π}}{2 e ^{2 π}}

Cancel

\frac{i e ^{4 π}}{2 e ^{2 π}} : \frac{i e ^{2 π}}{2}

\frac{i e ^{4 π}}{2 e ^{2 π}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{e ^{4 π}}{e ^{2 π}} = e^{4 π - 2 π}

= \frac{i e ^{4 π - 2 π}}{2}

Subtract the numbers:

4 π - 2 π = 2 π

= \frac{i e ^{2 π}}{2}

= \frac{i e ^{2 π}}{2}

= \frac{i e ^{2 π}}{2} - \frac{i}{2 e ^{2 π}}

Group the real part and the imaginary part of the complex number

= (\frac{e ^{2 π}}{2} - \frac{1}{2 e ^{2 π}}) i

\frac{e ^{2 π}}{2} - \frac{1}{2 e ^{2 π}} = \frac{e ^{4 π} - 1}{2 e ^{2 π}}

\frac{e ^{2 π}}{2} - \frac{1}{2 e ^{2 π}}

Least Common Multiplier of

2, 2 e^{2 π} : 2 e^{2 π}

2, 2 e^{2 π}

Lowest Common Multiplier (LCM)

Least Common Multiplier of

2, 2 : 2

2, 2

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Multiply each factor the greatest number of times it occurs in either

2

2

= 2

Multiply the numbers:

2 = 2

= 2

Compute an expression comprised of factors that appear either in

2

2 e^{2 π}

= 2 e^{2 π}

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

2 e^{2 π}

For

\frac{e ^{2 π}}{2} :

multiply the denominator and numerator by

e^{2 π}

\frac{e ^{2 π}}{2} = \frac{e ^{2 π} e ^{2 π}}{2 e ^{2 π}} = \frac{e ^{4 π}}{2 e ^{2 π}}

= \frac{e ^{4 π}}{2 e ^{2 π}} - \frac{1}{2 e ^{2 π}}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{4 π} - 1}{2 e ^{2 π}}

= \frac{e ^{4 π} - 1}{2 e ^{2 π}} i

= \frac{e ^{4 π} - 1}{2 e ^{2 π}} i

= i \frac{- 1 + e ^{4 π}}{2 e ^{2 π}}

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Frequently Asked Questions (FAQ)

What is the value of sin(2pii) ?
The value of sin(2pii) is i(-1+e^{4pi})/(2e^{2pi)}