What is the general solution for cos(θ)+1=0 ?

The general solution for cos(θ)+1=0 is θ=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)+1=0

cos (θ) + 1 = 0

θ = π + 2 πn

Degrees

θ = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) + 1 = 0

Move

1

to the right side

cos (θ) + 1 = 0

Subtract

1

from both sides

cos (θ) + 1 - 1 = 0 - 1

Simplify

cos (θ) = - 1

cos (θ) = - 1

General solutions for

cos (θ) = - 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = π + 2 πn

θ = π + 2 πn

sinh (0)

cos (2 t) = - \frac{3}{2}

sec (θ) = 2

tan (arccos (- \frac{12}{13}))

cos (3 0^{\circ})

What is the general solution for cos(θ)+1=0 ?
The general solution for cos(θ)+1=0 is θ=pi+2pin