What is the general solution for sin(x)=-(sqrt(3))/2 ?

The general solution for sin(x)=-(sqrt(3))/2 is x=(4pi)/3+2pin,x=(5pi)/3+2pin

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sin(x)=-(sqrt(3))/2

sin (x) = - \frac{3}{2}

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Degrees

x = 24 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) = - \frac{3}{2}

General solutions for

sin (x) = - \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

\frac{sin ( 0.001 )}{0.001}

tan (5 0^{\circ})

2 cos (\frac{π}{4})

sin (x) = - \frac{1}{2}

tan^{2} (x) = 3

What is the general solution for sin(x)=-(sqrt(3))/2 ?
The general solution for sin(x)=-(sqrt(3))/2 is x=(4pi)/3+2pin,x=(5pi)/3+2pin