What is the general solution for solvefor x,y=cos(y/(1.75))+x-0.5y^2 ?

The general solution for solvefor x,y=cos(y/(1.75))+x-0.5y^2 is x=y-cos(y/(1.75))+0.5y^2

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solvefor x,y=cos(y/(1.75))+x-0.5y^2

solve for

x, y = cos (\frac{y}{1.75}) + x - 0.5 y^{2}

x = y - cos (\frac{y}{1.75}) + 0.5 y^{2}

Solution steps

y = cos (\frac{y}{1.75}) + x - 0.5 y^{2}

Switch sides

cos (\frac{y}{1.75}) + x - 0.5 y^{2} = y

Move

cos (\frac{y}{1.75})

to the right side

cos (\frac{y}{1.75}) + x - 0.5 y^{2} = y

Subtract

cos (\frac{y}{1.75})

from both sides

cos (\frac{y}{1.75}) + x - 0.5 y^{2} - cos (\frac{y}{1.75}) = y - cos (\frac{y}{1.75})

Simplify

x - 0.5 y^{2} = y - cos (\frac{y}{1.75})

x - 0.5 y^{2} = y - cos (\frac{y}{1.75})

Move

0.5 y^{2}

to the right side

x - 0.5 y^{2} = y - cos (\frac{y}{1.75})

Add

0.5 y^{2}

to both sides

x - 0.5 y^{2} + 0.5 y^{2} = y - cos (\frac{y}{1.75}) + 0.5 y^{2}

Simplify

x = y - cos (\frac{y}{1.75}) + 0.5 y^{2}

x = y - cos (\frac{y}{1.75}) + 0.5 y^{2}

c, 2 sin^{3} (x) + cos^{2} (x) - cos (x) = 0

i, sin (x^{2}) + cos^{2} (x) + sin (x) + 1 = 0

t, tan^{2} (x) cot (x) = 1 + sec^{2} (x)

i, cos^{3} (x) + 2 sin (x) - 5 sin^{3} (x) = 0

sin (4 1^{\circ}) = \frac{x}{13}

What is the general solution for solvefor x,y=cos(y/(1.75))+x-0.5y^2 ?
The general solution for solvefor x,y=cos(y/(1.75))+x-0.5y^2 is x=y-cos(y/(1.75))+0.5y^2