What is the general solution for sin(30)=(x/(81)) ?

The general solution for sin(30)=(x/(81)) is x= 81/2

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sin(30)=(x/(81))

sin (3 0^{\circ}) = (\frac{x}{81})

x = \frac{81}{2}

Decimal Notation

x = 40.5

Solution steps

sin (3 0^{\circ}) = (\frac{x}{81})

Switch sides

(\frac{x}{81}) = sin (3 0^{\circ})

Simplify

sin (3 0^{\circ}) : \frac{1}{2}

sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

\frac{x}{81} = \frac{1}{2}

Multiply both sides by

81

\frac{x}{81} = \frac{1}{2}

Multiply both sides by

81

\frac{81 x}{81} = \frac{1 \cdot 81}{2}

Simplify

\frac{81 x}{81} = \frac{1 \cdot 81}{2}

Simplify

\frac{81 x}{81} : x

\frac{81 x}{81}

Divide the numbers:

\frac{81}{81} = 1

= x

Simplify

\frac{1 \cdot 81}{2} : \frac{81}{2}

\frac{1 \cdot 81}{2}

Multiply the numbers:

1 \cdot 81 = 81

= \frac{81}{2}

x = \frac{81}{2}

x = \frac{81}{2}

x = \frac{81}{2}

x, y = 2 \cdot x \cdot cos^{2} (y)

c, sin^{3} (x) + cos^{3} (x) = 4 cos (x) - 2 sin (x)

c, 3 (sin (x) + cos (x)) - sin^{2} (x) - 1 = 0

t, cot (x) cot^{2} (x) = - 1

i, 1 - 2 sin^{2} (4 5^{\circ} - \frac{a}{2}) = sin (a)

What is the general solution for sin(30)=(x/(81)) ?
The general solution for sin(30)=(x/(81)) is x= 81/2