What is the general solution for solvefor x,log_{10}(y)=arctan(x)+c ?

The general solution for solvefor x,log_{10}(y)=arctan(x)+c is x=tan(log_{10}(y)-c)

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solvefor x,log_{10}(y)=arctan(x)+c

solve for

x, lo g_{10} (y) = arctan (x) + c

x = tan (lo g_{10} (y) - c)

Solution steps

lo g_{10} (y) = arctan (x) + c

Switch sides

arctan (x) + c = lo g_{10} (y)

Move

c

to the right side

arctan (x) + c = lo g_{10} (y)

Subtract

c

from both sides

arctan (x) + c - c = lo g_{10} (y) - c

Simplify

arctan (x) = lo g_{10} (y) - c

arctan (x) = lo g_{10} (y) - c

Apply trig inverse properties

arctan (x) = lo g_{10} (y) - c

arctan (x) = a \Rightarrow x = tan (a)

x = tan (lo g_{10} (y) - c)

x = tan (lo g_{10} (y) - c)

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sin^{6} (x) - cos^{6} (x) = 0

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What is the general solution for solvefor x,log_{10}(y)=arctan(x)+c ?
The general solution for solvefor x,log_{10}(y)=arctan(x)+c is x=tan(log_{10}(y)-c)