What is the general solution for -4sin(8x)=0 ?

The general solution for -4sin(8x)=0 is x=(pin)/4 ,x= pi/8+(pin)/4

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-4sin(8x)=0

- 4 sin (8 x) = 0

x = \frac{πn}{4}, x = \frac{π}{8} + \frac{πn}{4}

Degrees

x = 0^{\circ} + 4 5^{\circ} n, x = 22. 5^{\circ} + 4 5^{\circ} n

Solution steps

- 4 sin (8 x) = 0

Divide both sides by

- 4

- 4 sin (8 x) = 0

Divide both sides by

- 4

\frac{- 4 sin ( 8 x )}{- 4} = \frac{0}{- 4}

Simplify

sin (8 x) = 0

sin (8 x) = 0

General solutions for

sin (8 x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

8 x = 0 + 2 πn, 8 x = π + 2 πn

8 x = 0 + 2 πn, 8 x = π + 2 πn

Solve

8 x = 0 + 2 πn : x = \frac{πn}{4}

8 x = 0 + 2 πn

0 + 2 πn = 2 πn

8 x = 2 πn

Divide both sides by

8

8 x = 2 πn

Divide both sides by

8

\frac{8 x}{8} = \frac{2 πn}{8}

Simplify

x = \frac{πn}{4}

x = \frac{πn}{4}

Solve

8 x = π + 2 πn : x = \frac{π}{8} + \frac{πn}{4}

8 x = π + 2 πn

Divide both sides by

8

8 x = π + 2 πn

Divide both sides by

8

\frac{8 x}{8} = \frac{π}{8} + \frac{2 πn}{8}

Simplify

x = \frac{π}{8} + \frac{πn}{4}

x = \frac{π}{8} + \frac{πn}{4}

x = \frac{πn}{4}, x = \frac{π}{8} + \frac{πn}{4}

- sin (x) + 2 cos (x) = 0

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

(cosh (x)) = sinh (x)

- 6 tan^{2} (θ) + 4 tan (θ) = - tan (θ) + 1

8 cos^{2} (x) + 14 cos (x) + 3 = 0

What is the general solution for -4sin(8x)=0 ?
The general solution for -4sin(8x)=0 is x=(pin)/4 ,x= pi/8+(pin)/4