What is the general solution for tan(θ)=-(sqrt(3))/3 ,0<= θ<= 2pi ?

The general solution for tan(θ)=-(sqrt(3))/3 ,0<= θ<= 2pi is θ=(5pi)/6 ,θ=(11pi)/6

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tan(θ)=-(sqrt(3))/3 ,0<= θ<= 2pi

tan (θ) = - \frac{3}{3}, 0 \leq θ \leq 2 π

θ = \frac{5 π}{6}, θ = \frac{11 π}{6}

Degrees

θ = 15 0^{\circ}, θ = 33 0^{\circ}

Solution steps

tan (θ) = - \frac{3}{3}, 0 \leq θ \leq 2 π

General solutions for

tan (θ) = - \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{5 π}{6} + πn

θ = \frac{5 π}{6} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{5 π}{6}, θ = \frac{11 π}{6}

cos (2 x) = sin (2 x) - 1

sinh^{2} (x) - 5 cosh (x) + 7 = 0

4 + 4 sin (x) = 0

tan (A) = \frac{67}{94}

sin (8 x) - 2 cos (4 x) = 0

What is the general solution for tan(θ)=-(sqrt(3))/3 ,0<= θ<= 2pi ?
The general solution for tan(θ)=-(sqrt(3))/3 ,0<= θ<= 2pi is θ=(5pi)/6 ,θ=(11pi)/6