What is the general solution for cos(θ)= 1/12 ?

The general solution for cos(θ)= 1/12 is θ=1.48736…+2pin,θ=2pi-1.48736…+2pin

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cos(θ)= 1/12

cos (θ) = \frac{1}{12}

θ = 1.48736 \dots + 2 πn, θ = 2 π - 1.48736 \dots + 2 πn

Degrees

θ = 85.21980 \dots^{\circ} + 36 0^{\circ} n, θ = 274.78019 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{1}{12}

Apply trig inverse properties

cos (θ) = \frac{1}{12}

General solutions for

cos (θ) = \frac{1}{12}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{1}{12}) + 2 πn, θ = 2 π - arccos (\frac{1}{12}) + 2 πn

θ = arccos (\frac{1}{12}) + 2 πn, θ = 2 π - arccos (\frac{1}{12}) + 2 πn

Show solutions in decimal form

θ = 1.48736 \dots + 2 πn, θ = 2 π - 1.48736 \dots + 2 πn

sin (θ) = - \frac{8}{9}

2 sin^{2} (x) + 5 sin (x) - 12 = 0

3 tan (x - \frac{π}{5}) - 1 = 0

x, 0 = 4 - \frac{1}{cos ^{2} ( x )}

tan (θ) = \frac{17}{12}

What is the general solution for cos(θ)= 1/12 ?
The general solution for cos(θ)= 1/12 is θ=1.48736…+2pin,θ=2pi-1.48736…+2pin