What is the general solution for sin^2(x)-6sin(x)=0 ?

The general solution for sin^2(x)-6sin(x)=0 is x=2pin,x=pi+2pin

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sin^2(x)-6sin(x)=0

Solution

sin^{2} (x) - 6 sin (x) = 0

Solution

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

sin^{2} (x) - 6 sin (x) = 0

Solve by substitution

sin^{2} (x) - 6 sin (x) = 0

Let:

sin (x) = u

u^{2} - 6 u = 0

u^{2} - 6 u = 0 : u = 6, u = 0

u^{2} - 6 u = 0

Solve with the quadratic formula

u^{2} - 6 u = 0

Quadratic Equation Formula:

For

a = 1, b = - 6, c = 0

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

(- 6)^{2} - 4 \cdot 1 \cdot 0

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2}

= 6^{2} - 4 \cdot 1 \cdot 0

Apply rule

0 \cdot a = 0

= 6^{2} - 0

6^{2} - 0 = 6^{2}

= 6^{2}

Apply radical rule:

assuming

a \geq 0

= 6

u_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, u_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

u = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

\frac{- ( - 6 ) + 6}{2 \cdot 1}

Apply rule

- (- a) = a

= \frac{6 + 6}{2 \cdot 1}

Add the numbers:

6 + 6 = 12

= \frac{12}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{12}{2}

Divide the numbers:

\frac{12}{2} = 6

= 6

u = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

\frac{- ( - 6 ) - 6}{2 \cdot 1}

Apply rule

- (- a) = a

= \frac{6 - 6}{2 \cdot 1}

Subtract the numbers:

6 - 6 = 0

= \frac{0}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{0}{2}

Apply rule

\frac{0}{a} = 0, a \neq = 0

= 0

The solutions to the quadratic equation are:

u = 6, u = 0

Substitute back

u = sin (x)

sin (x) = 6, sin (x) = 0

sin (x) = 6, sin (x) = 0

sin (x) = 6 :

No Solution

sin (x) = 6

- 1 \leq sin (x) \leq 1

No Solution

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

Popular Examples

cos(a)= 3/3

cos (a) = \frac{3}{3}

3csc^2(x)-2csc(x)-5=0

3 csc^{2} (x) - 2 csc (x) - 5 = 0

cos(2x-1)=0.4

cos (2 x - 1) = 0.4

cos(3x)cos(x)=2cos(2x)cos(x)

cos (3 x) cos (x) = 2 cos (2 x) cos (x)

0=cos(2x)-cos(x)

0 = cos (2 x) - cos (x)

Frequently Asked Questions (FAQ)

What is the general solution for sin^2(x)-6sin(x)=0 ?
The general solution for sin^2(x)-6sin(x)=0 is x=2pin,x=pi+2pin