What is the general solution for solvefor θ,cos(θ/2+30)=sin(θ) ?

The general solution for solvefor θ,cos(θ/2+30)=sin(θ) is θ=(360+2160n)/9 ,θ=(720+2160n)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor θ,cos(θ/2+30)=sin(θ)

Solution

solve for

θ, cos (\frac{θ}{2} + 3 0^{\circ}) = sin (θ)

Solution

θ = \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}, θ = \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

Radians

θ = \frac{2 π}{9} + \frac{12 π}{9} n, θ = \frac{4 π}{3} + \frac{12 π}{3} n

Solution steps

cos (\frac{θ}{2} + 3 0^{\circ}) = sin (θ)

Rewrite using trig identities

cos (\frac{θ}{2} + 3 0^{\circ}) = sin (θ)

Use the following identity:

cos (x) = sin (9 0^{\circ} - x)

cos (\frac{θ}{2} + 3 0^{\circ}) = sin (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}))

cos (\frac{θ}{2} + 3 0^{\circ}) = sin (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}))

Apply trig inverse properties

cos (\frac{θ}{2} + 3 0^{\circ}) = sin (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}))

sin (x) = sin (y) \Rightarrow x = y + 2 π n, x = π - y + 2 π n

θ = 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n, θ = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n

θ = 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n, θ = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n

θ = 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n : θ = \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}

θ = 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n

Move

(\frac{θ}{2} + 3 0^{\circ})

to the left side

θ = 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n

Add

(\frac{θ}{2} + 3 0^{\circ})

to both sides

θ + \frac{θ}{2} + 3 0^{\circ} = 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n + \frac{θ}{2} + 3 0^{\circ}

Simplify

θ + \frac{θ}{2} + 3 0^{\circ} = 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n + \frac{θ}{2} + 3 0^{\circ}

Simplify

θ + \frac{θ}{2} + 3 0^{\circ} : \frac{9 θ + 18 0 ^{\circ}}{6}

θ + \frac{θ}{2} + 3 0^{\circ}

Convert element to fraction:

θ = \frac{θ}{1}

= \frac{θ}{2} + 3 0^{\circ} + \frac{θ}{1}

Least Common Multiplier of

2, 6, 1 : 6

2, 6, 1

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Prime factorization of

1

Compute a number comprised of factors that appear in at least one of the following:

2, 6, 1

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{θ}{2} :

multiply the denominator and numerator by

3

\frac{θ}{2} = \frac{θ \cdot 3}{2 \cdot 3} = \frac{θ \cdot 3}{6}

For

\frac{θ}{1} :

multiply the denominator and numerator by

6

\frac{θ}{1} = \frac{θ \cdot 6}{1 \cdot 6} = \frac{θ \cdot 6}{6}

= \frac{θ \cdot 3}{6} + 3 0^{\circ} + \frac{θ \cdot 6}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{θ \cdot 3 + 18 0 ^{\circ} + θ \cdot 6}{6}

θ \cdot 3 + 18 0^{\circ} + θ \cdot 6 = 9 θ + 18 0^{\circ}

θ \cdot 3 + 18 0^{\circ} + θ \cdot 6

Group like terms

= 3 θ + 6 θ + 18 0^{\circ}

Add similar elements:

3 θ + 6 θ = 9 θ

= 9 θ + 18 0^{\circ}

= \frac{9 θ + 18 0 ^{\circ}}{6}

Simplify

9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n + \frac{θ}{2} + 3 0^{\circ} : 9 0^{\circ} + 36 0^{\circ} n

9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) + 36 0^{\circ} n + \frac{θ}{2} + 3 0^{\circ}

Add similar elements:

- (\frac{θ}{2} + 3 0^{\circ}) + \frac{θ}{2} + 3 0^{\circ} = 0

= 9 0^{\circ} + 36 0^{\circ} n

\frac{9 θ + 18 0 ^{\circ}}{6} = 9 0^{\circ} + 36 0^{\circ} n

\frac{9 θ + 18 0 ^{\circ}}{6} = 9 0^{\circ} + 36 0^{\circ} n

\frac{9 θ + 18 0 ^{\circ}}{6} = 9 0^{\circ} + 36 0^{\circ} n

Multiply both sides by

6

\frac{9 θ + 18 0 ^{\circ}}{6} = 9 0^{\circ} + 36 0^{\circ} n

Multiply both sides by

6

\frac{6 ( 9 θ + 18 0 ^{\circ} )}{6} = 6 \cdot 9 0^{\circ} + 6 \cdot 36 0^{\circ} n

Simplify

\frac{6 ( 9 θ + 18 0 ^{\circ} )}{6} = 6 \cdot 9 0^{\circ} + 6 \cdot 36 0^{\circ} n

Simplify

\frac{6 ( 9 θ + 18 0 ^{\circ} )}{6} : 9 θ + 18 0^{\circ}

\frac{6 ( 9 θ + 18 0 ^{\circ} )}{6}

Divide the numbers:

\frac{6}{6} = 1

= 9 θ + 18 0^{\circ}

Simplify

6 \cdot 9 0^{\circ} + 6 \cdot 36 0^{\circ} n : 54 0^{\circ} + 216 0^{\circ} n

6 \cdot 9 0^{\circ} + 6 \cdot 36 0^{\circ} n

6 \cdot 9 0^{\circ} = 54 0^{\circ}

6 \cdot 9 0^{\circ}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 54 0^{\circ}

Divide the numbers:

\frac{6}{2} = 3

= 54 0^{\circ}

6 \cdot 36 0^{\circ} n = 216 0^{\circ} n

6 \cdot 36 0^{\circ} n

Multiply the numbers:

6 \cdot 2 = 12

= 216 0^{\circ} n

= 54 0^{\circ} + 216 0^{\circ} n

9 θ + 18 0^{\circ} = 54 0^{\circ} + 216 0^{\circ} n

9 θ + 18 0^{\circ} = 54 0^{\circ} + 216 0^{\circ} n

9 θ + 18 0^{\circ} = 54 0^{\circ} + 216 0^{\circ} n

Move

18 0^{\circ}

to the right side

9 θ + 18 0^{\circ} = 54 0^{\circ} + 216 0^{\circ} n

Subtract

18 0^{\circ}

from both sides

9 θ + 18 0^{\circ} - 18 0^{\circ} = 54 0^{\circ} + 216 0^{\circ} n - 18 0^{\circ}

Simplify

9 θ = 36 0^{\circ} + 216 0^{\circ} n

9 θ = 36 0^{\circ} + 216 0^{\circ} n

Divide both sides by

9

9 θ = 36 0^{\circ} + 216 0^{\circ} n

Divide both sides by

9

\frac{9 θ}{9} = 4 0^{\circ} + \frac{216 0 ^{\circ} n}{9}

Simplify

\frac{9 θ}{9} = 4 0^{\circ} + \frac{216 0 ^{\circ} n}{9}

Simplify

\frac{9 θ}{9} : θ

\frac{9 θ}{9}

Divide the numbers:

\frac{9}{9} = 1

= θ

Simplify

4 0^{\circ} + \frac{216 0 ^{\circ} n}{9} : \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}

4 0^{\circ} + \frac{216 0 ^{\circ} n}{9}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}

θ = \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}

θ = \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}

θ = \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}

θ = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n : θ = \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

θ = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n

Move

(9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}))

to the left side

θ = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n

Add

(9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}))

to both sides

θ + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})

Simplify

θ + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})

Simplify

θ + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) : \frac{3 θ + 36 0 ^{\circ}}{6}

θ + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})

- (\frac{θ}{2} + 3 0^{\circ}) : - \frac{θ}{2} - 3 0^{\circ}

- (\frac{θ}{2} + 3 0^{\circ})

Distribute parentheses

= - (\frac{θ}{2}) - (3 0^{\circ})

Apply minus-plus rules

+ (- a) = - a

= - \frac{θ}{2} - 3 0^{\circ}

= θ + 9 0^{\circ} - \frac{θ}{2} - 3 0^{\circ}

Simplify

θ + 9 0^{\circ} - \frac{θ}{2} - 3 0^{\circ} : \frac{3 θ + 36 0 ^{\circ}}{6}

θ + 9 0^{\circ} - \frac{θ}{2} - 3 0^{\circ}

Group like terms

= θ - \frac{θ}{2} + 9 0^{\circ} - 3 0^{\circ}

Combine the fractions

- \frac{θ}{2} + 9 0^{\circ} : \frac{- θ + 18 0 ^{\circ}}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- θ + 18 0 ^{\circ}}{2}

= θ + \frac{- θ + 18 0 ^{\circ}}{2} - 3 0^{\circ}

Convert element to fraction:

θ = \frac{θ}{1}

= \frac{- θ + 18 0 ^{\circ}}{2} - 3 0^{\circ} + \frac{θ}{1}

Least Common Multiplier of

2, 6, 1 : 6

2, 6, 1

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Prime factorization of

1

Compute a number comprised of factors that appear in at least one of the following:

2, 6, 1

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{- θ + 18 0 ^{\circ}}{2} :

multiply the denominator and numerator by

3

\frac{- θ + 18 0 ^{\circ}}{2} = \frac{( - θ + 18 0 ^{\circ} ) \cdot 3}{2 \cdot 3} = \frac{( - θ + 18 0 ^{\circ} ) \cdot 3}{6}

For

\frac{θ}{1} :

multiply the denominator and numerator by

6

\frac{θ}{1} = \frac{θ \cdot 6}{1 \cdot 6} = \frac{θ \cdot 6}{6}

= \frac{( - θ + 18 0 ^{\circ} ) \cdot 3}{6} - 3 0^{\circ} + \frac{θ \cdot 6}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( - θ + 18 0 ^{\circ} ) \cdot 3 - 18 0 ^{\circ} + θ \cdot 6}{6}

Expand

(- θ + 18 0^{\circ}) \cdot 3 - 18 0^{\circ} + θ \cdot 6 : 3 θ + 36 0^{\circ}

(- θ + 18 0^{\circ}) \cdot 3 - 18 0^{\circ} + θ \cdot 6

= 3 (- θ + 18 0^{\circ}) - 18 0^{\circ} + 6 θ

Expand

3 (- θ + 18 0^{\circ}) : - 3 θ + 54 0^{\circ}

3 (- θ + 18 0^{\circ})

Apply the distributive law:

a (b + c) = ab + a c

a = 3, b = - θ, c = 18 0^{\circ}

= 3 (- θ) + 54 0^{\circ}

Apply minus-plus rules

+ (- a) = - a

= - 3 θ + 54 0^{\circ}

= - 3 θ + 54 0^{\circ} - 18 0^{\circ} + θ \cdot 6

Simplify

- 3 θ + 54 0^{\circ} - 18 0^{\circ} + θ \cdot 6 : 3 θ + 36 0^{\circ}

- 3 θ + 54 0^{\circ} - 18 0^{\circ} + θ \cdot 6

Group like terms

= - 3 θ + 6 θ + 54 0^{\circ} - 18 0^{\circ}

Add similar elements:

- 3 θ + 6 θ = 3 θ

= 3 θ + 54 0^{\circ} - 18 0^{\circ}

Add similar elements:

54 0^{\circ} - 18 0^{\circ} = 36 0^{\circ}

= 3 θ + 36 0^{\circ}

= 3 θ + 36 0^{\circ}

= \frac{3 θ + 36 0 ^{\circ}}{6}

= \frac{3 θ + 36 0 ^{\circ}}{6}

Simplify

18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) : 18 0^{\circ} + 36 0^{\circ} n

18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 36 0^{\circ} n + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})

Add similar elements:

- (9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ})) + 9 0^{\circ} - (\frac{θ}{2} + 3 0^{\circ}) = 0

= 18 0^{\circ} + 36 0^{\circ} n

\frac{3 θ + 36 0 ^{\circ}}{6} = 18 0^{\circ} + 36 0^{\circ} n

\frac{3 θ + 36 0 ^{\circ}}{6} = 18 0^{\circ} + 36 0^{\circ} n

\frac{3 θ + 36 0 ^{\circ}}{6} = 18 0^{\circ} + 36 0^{\circ} n

Multiply both sides by

6

\frac{3 θ + 36 0 ^{\circ}}{6} = 18 0^{\circ} + 36 0^{\circ} n

Multiply both sides by

6

\frac{6 ( 3 θ + 36 0 ^{\circ} )}{6} = 108 0^{\circ} + 6 \cdot 36 0^{\circ} n

Simplify

3 θ + 36 0^{\circ} = 108 0^{\circ} + 216 0^{\circ} n

3 θ + 36 0^{\circ} = 108 0^{\circ} + 216 0^{\circ} n

Move

36 0^{\circ}

to the right side

3 θ + 36 0^{\circ} = 108 0^{\circ} + 216 0^{\circ} n

Subtract

36 0^{\circ}

from both sides

3 θ + 36 0^{\circ} - 36 0^{\circ} = 108 0^{\circ} + 216 0^{\circ} n - 36 0^{\circ}

Simplify

3 θ = 72 0^{\circ} + 216 0^{\circ} n

3 θ = 72 0^{\circ} + 216 0^{\circ} n

Divide both sides by

3

3 θ = 72 0^{\circ} + 216 0^{\circ} n

Divide both sides by

3

\frac{3 θ}{3} = 24 0^{\circ} + \frac{216 0 ^{\circ} n}{3}

Simplify

\frac{3 θ}{3} = 24 0^{\circ} + \frac{216 0 ^{\circ} n}{3}

Simplify

\frac{3 θ}{3} : θ

\frac{3 θ}{3}

Divide the numbers:

\frac{3}{3} = 1

= θ

Simplify

24 0^{\circ} + \frac{216 0 ^{\circ} n}{3} : \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

24 0^{\circ} + \frac{216 0 ^{\circ} n}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

θ = \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

θ = \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

θ = \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

θ = \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}, θ = \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

θ = \frac{36 0 ^{\circ} + 216 0 ^{\circ} n}{9}, θ = \frac{72 0 ^{\circ} + 216 0 ^{\circ} n}{3}

Popular Examples

5sin^2(θ)=1+3sin^2(θ)

5 sin^{2} (θ) = 1 + 3 sin^{2} (θ)

5sin(2θ)-8sin(θ)=0

5 sin (2 θ) - 8 sin (θ) = 0

tan(θ)=(5sqrt(3))/5

tan (θ) = \frac{5 3}{5}

solvefor f,r= 8/(sec(f^0))solve for

f, r = \frac{8}{sec ( f ^{0} )}

2sin(x)-sqrt(2)=0,0<= x<= 2pi

2 sin (x) - 2 = 0, 0 \leq x \leq 2 π

Frequently Asked Questions (FAQ)

What is the general solution for solvefor θ,cos(θ/2+30)=sin(θ) ?
The general solution for solvefor θ,cos(θ/2+30)=sin(θ) is θ=(360+2160n)/9 ,θ=(720+2160n)/3