What is the general solution for tan(x)=1,0<= x<2pi ?

The general solution for tan(x)=1,0<= x<2pi is x= pi/4 ,x=(5pi)/4

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tan(x)=1,0<= x<2pi

tan (x) = 1, 0 \leq x < 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Degrees

x = 4 5^{\circ}, x = 22 5^{\circ}

Solution steps

tan (x) = 1, 0 \leq x < 2 π

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

x, sin (2 x) \cdot cos (2 x) = 0.5

2 sin^{2} (x) + sin (x) - 3 = 0, 6

(1 - sin (2 x)) \cdot (1 - cos^{2} (x)) = 0

5 cos (x) - 10 sin (x) cos (x) = 0, 0 \leq x \leq \frac{π}{2}

∣ (211) ∣ ∣ (- 37 - 1) ∣ (cos (x)) = 0

What is the general solution for tan(x)=1,0<= x<2pi ?
The general solution for tan(x)=1,0<= x<2pi is x= pi/4 ,x=(5pi)/4