What is the general solution for 7-5cos(x)=10,7-5cos(x)=10 ?

The general solution for 7-5cos(x)=10,7-5cos(x)=10 is No Solution for x\in\mathbb{R}

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7-5cos(x)=10,7-5cos(x)=10

7 - 5 cos (x) = 10, 7 - 5 cos (x) = 10

No Solution for x \in R

Solution steps

7 - 5 cos (x) = 10, 7 - 5 cos (x) = 10

Move

7

to the right side

7 - 5 cos (x) = 10

Subtract

7

from both sides

7 - 5 cos (x) - 7 = 10 - 7

Simplify

- 5 cos (x) = 3

- 5 cos (x) = 3

Divide both sides by

- 5

- 5 cos (x) = 3

Divide both sides by

- 5

\frac{- 5 cos ( x )}{- 5} = \frac{3}{- 5}

Simplify

cos (x) = - \frac{3}{5}

cos (x) = - \frac{3}{5}

Apply trig inverse properties

cos (x) = - \frac{3}{5}

General solutions for

cos (x) = - \frac{3}{5}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- \frac{3}{5}) + 2 πn, x = - arccos (- \frac{3}{5}) + 2 πn

x = arccos (- \frac{3}{5}) + 2 πn, x = - arccos (- \frac{3}{5}) + 2 πn

Solutions for the range

7 - 5 cos (x) = 10

No Solution for x \in R

cos (4 x) = cos (x)

- 4 cos (2 θ) - 19 = - 26 cos (θ), 0 \leq θ < 36 0^{\circ}

3 cos^{2} (x) = 7 - 8 sin (x)

sin (X) = - \frac{1}{2}

- 2 (sin (2 t) - cos (t)) = 0

What is the general solution for 7-5cos(x)=10,7-5cos(x)=10 ?
The general solution for 7-5cos(x)=10,7-5cos(x)=10 is No Solution for x\in\mathbb{R}