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cos^3(x)= 1/(4(3cos(x)+cos(3x)))

Solution

cos^{3} (x) = \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

Solution

x = 0.88929 \dots + 2 πn, x = 2 π - 0.88929 \dots + 2 πn, x = 2.25229 \dots + 2 πn, x = - 2.25229 \dots + 2 πn

Degrees

x = 50.95278 \dots^{\circ} + 36 0^{\circ} n, x = 309.04721 \dots^{\circ} + 36 0^{\circ} n, x = 129.04721 \dots^{\circ} + 36 0^{\circ} n, x = - 129.04721 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos^{3} (x) = \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

Subtract

\frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

from both sides

cos^{3} (x) - \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )} = 0

Simplify

cos^{3} (x) - \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )} : \frac{4 cos ^{3} ( x ) ( 3 cos ( x ) + cos ( 3 x ) ) - 1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

cos^{3} (x) - \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

Convert element to fraction:

cos^{3} (x) = \frac{cos ^{3} ( x ) 4 ( 3 cos ( x ) + cos ( 3 x ) )}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

= \frac{cos ^{3} ( x ) \cdot 4 ( 3 cos ( x ) + cos ( 3 x ) )}{4 ( 3 cos ( x ) + cos ( 3 x ) )} - \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ^{3} ( x ) \cdot 4 ( 3 cos ( x ) + cos ( 3 x ) ) - 1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

\frac{4 cos ^{3} ( x ) ( 3 cos ( x ) + cos ( 3 x ) ) - 1}{4 ( 3 cos ( x ) + cos ( 3 x ) )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

4 cos^{3} (x) (3 cos (x) + cos (3 x)) - 1 = 0

Rewrite using trig identities

- 1 + (cos (3 x) + 3 cos (x)) \cdot 4 cos^{3} (x)

cos (3 x) = 4 cos^{3} (x) - 3 cos (x)

cos (3 x)

Rewrite using trig identities

cos (3 x)

Rewrite as

= cos (2 x + x)

Use the Angle Sum identity:

cos (s + t) = cos (s) cos (t) - sin (s) sin (t)

= cos (2 x) cos (x) - sin (2 x) sin (x)

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

= cos (2 x) cos (x) - 2 sin (x) cos (x) sin (x)

Simplify

cos (2 x) cos (x) - 2 sin (x) cos (x) sin (x) : cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

cos (2 x) cos (x) - 2 sin (x) cos (x) sin (x)

2 sin (x) cos (x) sin (x) = 2 sin^{2} (x) cos (x)

2 sin (x) cos (x) sin (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= 2 cos (x) sin^{1 + 1} (x)

Add the numbers:

1 + 1 = 2

= 2 cos (x) sin^{2} (x)

= cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

= cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

= cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

Use the Double Angle identity:

cos (2 x) = 2 cos^{2} (x) - 1

= (2 cos^{2} (x) - 1) cos (x) - 2 sin^{2} (x) cos (x)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= (2 cos^{2} (x) - 1) cos (x) - 2 (1 - cos^{2} (x)) cos (x)

Expand

(2 cos^{2} (x) - 1) cos (x) - 2 (1 - cos^{2} (x)) cos (x) : 4 cos^{3} (x) - 3 cos (x)

(2 cos^{2} (x) - 1) cos (x) - 2 (1 - cos^{2} (x)) cos (x)

= cos (x) (2 cos^{2} (x) - 1) - 2 cos (x) (1 - cos^{2} (x))

Expand

cos (x) (2 cos^{2} (x) - 1) : 2 cos^{3} (x) - cos (x)

cos (x) (2 cos^{2} (x) - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = cos (x), b = 2 cos^{2} (x), c = 1

= cos (x) 2 cos^{2} (x) - cos (x) 1

= 2 cos^{2} (x) cos (x) - 1 cos (x)

Simplify

2 cos^{2} (x) cos (x) - 1 \cdot cos (x) : 2 cos^{3} (x) - cos (x)

2 cos^{2} (x) cos (x) - 1 cos (x)

2 cos^{2} (x) cos (x) = 2 cos^{3} (x)

2 cos^{2} (x) cos (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

cos^{2} (x) cos (x) = cos^{2 + 1} (x)

= 2 cos^{2 + 1} (x)

Add the numbers:

2 + 1 = 3

= 2 cos^{3} (x)

1 \cdot cos (x) = cos (x)

1 cos (x)

Multiply:

1 \cdot cos (x) = cos (x)

= cos (x)

= 2 cos^{3} (x) - cos (x)

= 2 cos^{3} (x) - cos (x)

= 2 cos^{3} (x) - cos (x) - 2 (1 - cos^{2} (x)) cos (x)

Expand

- 2 cos (x) (1 - cos^{2} (x)) : - 2 cos (x) + 2 cos^{3} (x)

- 2 cos (x) (1 - cos^{2} (x))

Apply the distributive law:

a (b - c) = ab - a c

a = - 2 cos (x), b = 1, c = cos^{2} (x)

= - 2 cos (x) 1 - (- 2 cos (x)) cos^{2} (x)

Apply minus-plus rules

- (- a) = a

= - 2 \cdot 1 cos (x) + 2 cos^{2} (x) cos (x)

Simplify

- 2 \cdot 1 \cdot cos (x) + 2 cos^{2} (x) cos (x) : - 2 cos (x) + 2 cos^{3} (x)

- 2 \cdot 1 cos (x) + 2 cos^{2} (x) cos (x)

2 \cdot 1 \cdot cos (x) = 2 cos (x)

2 \cdot 1 cos (x)

Multiply the numbers:

2 \cdot 1 = 2

= 2 cos (x)

2 cos^{2} (x) cos (x) = 2 cos^{3} (x)

2 cos^{2} (x) cos (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

cos^{2} (x) cos (x) = cos^{2 + 1} (x)

= 2 cos^{2 + 1} (x)

Add the numbers:

2 + 1 = 3

= 2 cos^{3} (x)

= - 2 cos (x) + 2 cos^{3} (x)

= - 2 cos (x) + 2 cos^{3} (x)

= 2 cos^{3} (x) - cos (x) - 2 cos (x) + 2 cos^{3} (x)

Simplify

2 cos^{3} (x) - cos (x) - 2 cos (x) + 2 cos^{3} (x) : 4 cos^{3} (x) - 3 cos (x)

2 cos^{3} (x) - cos (x) - 2 cos (x) + 2 cos^{3} (x)

Group like terms

= 2 cos^{3} (x) + 2 cos^{3} (x) - cos (x) - 2 cos (x)

Add similar elements:

2 cos^{3} (x) + 2 cos^{3} (x) = 4 cos^{3} (x)

= 4 cos^{3} (x) - cos (x) - 2 cos (x)

Add similar elements:

- cos (x) - 2 cos (x) = - 3 cos (x)

= 4 cos^{3} (x) - 3 cos (x)

= 4 cos^{3} (x) - 3 cos (x)

= 4 cos^{3} (x) - 3 cos (x)

= - 1 + 4 cos^{3} (x) (4 cos^{3} (x) - 3 cos (x) + 3 cos (x))

4 cos^{3} (x) (4 cos^{3} (x) - 3 cos (x) + 3 cos (x)) = 16 cos^{6} (x)

4 cos^{3} (x) (4 cos^{3} (x) - 3 cos (x) + 3 cos (x))

Add similar elements:

- 3 cos (x) + 3 cos (x) = 0

= 4 \cdot 4 cos^{3} (x) cos^{3} (x)

Multiply the numbers:

4 \cdot 4 = 16

= 16 cos^{3} (x) cos^{3} (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

cos^{3} (x) cos^{3} (x) = cos^{3 + 3} (x)

= 16 cos^{3 + 3} (x)

Add the numbers:

3 + 3 = 6

= 16 cos^{6} (x)

= - 1 + 16 cos^{6} (x)

- 1 + 16 cos^{6} (x) = 0

Solve by substitution

- 1 + 16 cos^{6} (x) = 0

Let:

cos (x) = w

- 1 + 16 w^{6} = 0

- 1 + 16 w^{6} = 0

Move

1

to the right side

- 1 + 16 w^{6} = 0

Add

1

to both sides

- 1 + 16 w^{6} + 1 = 0 + 1

Simplify

16 w^{6} = 1

16 w^{6} = 1

Divide both sides by

16

16 w^{6} = 1

Divide both sides by

16

\frac{16 w ^{6}}{16} = \frac{1}{16}

Simplify

w^{6} = \frac{1}{16}

w^{6} = \frac{1}{16}

Rewrite the equation with

u = w^{2}

and

u^{3} = w^{6}

u^{3} = \frac{1}{16}

Solve

u^{3} = \frac{1}{16}

For

g^{3} (x) = f (a)

the solutions are

Substitute back

u = w^{2},

solve for

w

Solve

Simplify

Apply radical rule:

assuming

a \geq 0, b \geq 0

Prime factorization of

16 : 2^{4}

16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2

2

is a prime number, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2

= 2^{4}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

Apply radical rule:

Apply rule

Rationalize

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

1 \cdot 2^{\frac{2}{3}} = 2^{\frac{2}{3}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 2^{1 + \frac{2}{3} + \frac{1}{3}}

Join

1 + \frac{2}{3} + \frac{1}{3} : 2

1 + \frac{2}{3} + \frac{1}{3}

Convert element to fraction:

1 = \frac{1}{1}

= \frac{1}{1} + \frac{2}{3} + \frac{1}{3}

Least Common Multiplier of

1, 3, 3 : 3

1, 3, 3

Least Common Multiplier (LCM)

Prime factorization of

1

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Compute a number comprised of factors that appear in at least one of the following:

1, 3, 3

= 3

Multiply the numbers:

3 = 3

= 3

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

3

For

\frac{1}{1} :

multiply the denominator and numerator by

3

\frac{1}{1} = \frac{1 \cdot 3}{1 \cdot 3} = \frac{3}{3}

= \frac{3}{3} + \frac{2}{3} + \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 + 2 + 1}{3}

Add the numbers:

3 + 2 + 1 = 6

= \frac{6}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2

= 2^{2}

2^{2} = 4

= 4

= \frac{2 ^{\frac{2}{3}}}{4}

= \frac{2 ^{\frac{2}{3}}}{4}

w^{2} = \frac{2 ^{\frac{2}{3}}}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = \frac{2 ^{\frac{2}{3}}}{4}, w = - \frac{2 ^{\frac{2}{3}}}{4}

\frac{2 ^{\frac{2}{3}}}{4} = \frac{2 ^{\frac{2}{3}}}{2}

\frac{2 ^{\frac{2}{3}}}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{2 ^{\frac{2}{3}}}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{2 ^{\frac{2}{3}}}{2}

- \frac{2 ^{\frac{2}{3}}}{4} = - \frac{2 ^{\frac{2}{3}}}{2}

- \frac{2 ^{\frac{2}{3}}}{4}

Simplify

\frac{2 ^{\frac{2}{3}}}{4} : \frac{2 ^{\frac{2}{3}}}{2}

\frac{2 ^{\frac{2}{3}}}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{2 ^{\frac{2}{3}}}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{2 ^{\frac{2}{3}}}{2}

= - \frac{2 ^{\frac{2}{3}}}{2}

w = \frac{2 ^{\frac{2}{3}}}{2}, w = - \frac{2 ^{\frac{2}{3}}}{2}

Solve

Substitute

w = u + v i

Expand

(u + v i)^{2} : (u^{2} - v^{2}) + 2 i uv

(u + v i)^{2}

= (u + i v)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = u, b = v i

= u^{2} + 2 uv i + (v i)^{2}

(v i)^{2} = - v^{2}

(v i)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= i^{2} v^{2}

i^{2} = - 1

i^{2}

Apply imaginary number rule:

i^{2} = - 1

= - 1

= (- 1) v^{2}

Refine

= - v^{2}

= u^{2} + 2 i uv - v^{2}

Rewrite

u^{2} + 2 i uv - v^{2}

in standard complex form:

(u^{2} - v^{2}) + 2 uv i

u^{2} + 2 i uv - v^{2}

Group the real part and the imaginary part of the complex number

= (u^{2} - v^{2}) + 2 uv i

= (u^{2} - v^{2}) + 2 uv i

Expand

Apply radical rule:

assuming

a \geq 0, b \geq 0

Prime factorization of

16 : 2^{4}

16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2

2

is a prime number, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2

= 2^{4}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

Apply radical rule:

Apply rule

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

1 \cdot (- 1 + 3 i) = - 1 + 3 i

1 \cdot (- 1 + 3 i)

Multiply:

1 \cdot (- 1 + 3 i) = (- 1 + 3 i)

= (- 1 + 3 i)

Remove parentheses:

(- a) = - a

= - 1 + 3 i

Multiply the numbers:

2 \cdot 2 = 4

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

Rewrite

in standard complex form:

- \frac{2 ^{\frac{2}{3}}}{8} + \frac{3 \cdot 2 ^{\frac{2}{3}}}{8} i

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4 \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

1 \cdot 2^{\frac{2}{3}} = 2^{\frac{2}{3}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4 \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= - \frac{2 ^{\frac{2}{3}}}{8}

= - \frac{2 ^{\frac{2}{3}}}{8} + \frac{3 \cdot 2 ^{\frac{2}{3}}}{8} i

= - \frac{2 ^{\frac{2}{3}}}{8} + \frac{3 \cdot 2 ^{\frac{2}{3}}}{8} i

(u^{2} - v^{2}) + 2 i uv = - \frac{2 ^{\frac{2}{3}}}{8} + i \frac{2 ^{\frac{2}{3}} 3}{8}

(u^{2} - v^{2}) + 2 i uv = - \frac{2 ^{\frac{2}{3}}}{8} + i \frac{2 ^{\frac{2}{3}} 3}{8}

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} 2 uv = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}]

[u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} 2 uv = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}]

Isolate

u

for

2 uv = \frac{2 ^{\frac{2}{3}} \cdot 3}{8} : u = \frac{3}{2 ^{\frac{10}{3}} v}

2 uv = \frac{2 ^{\frac{2}{3}} 3}{8}

Simplify

\frac{2 ^{\frac{2}{3}} 3}{8} : \frac{3}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}} 3}{8}

Factor the number:

8 = 2^{3}

= \frac{2 ^{\frac{2}{3}} 3}{2 ^{3}}

Simplify

\frac{2 ^{\frac{2}{3}}}{2 ^{3}} : \frac{1}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

= \frac{1}{2 ^{3 - \frac{2}{3}}}

3 - \frac{2}{3} = \frac{7}{3}

3 - \frac{2}{3}

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= \frac{3 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 3 - 2}{3}

3 \cdot 3 - 2 = 7

3 \cdot 3 - 2

Multiply the numbers:

3 \cdot 3 = 9

= 9 - 2

Subtract the numbers:

9 - 2 = 7

= 7

= \frac{7}{3}

= \frac{1}{2 ^{\frac{7}{3}}}

= \frac{3}{2 ^{\frac{7}{3}}}

2 uv = \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 v

2 uv = \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 v

\frac{2 uv}{2 v} = \frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 v}

Simplify

\frac{2 uv}{2 v} = \frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 v}

Simplify

\frac{2 uv}{2 v} : u

\frac{2 uv}{2 v}

Cancel the common factor:

2

= \frac{uv}{v}

Cancel the common factor:

v

= u

Simplify

\frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 v} : \frac{3}{2 ^{\frac{10}{3}} v}

\frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 v}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{3}{2 ^{\frac{7}{3}} \cdot 2 v}

2^{\frac{7}{3}} \cdot 2 = 2^{\frac{10}{3}}

2^{\frac{7}{3}} \cdot 2

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{7}{3}} \cdot 2 = 2^{\frac{7}{3} + 1}

= 2^{\frac{7}{3} + 1}

\frac{7}{3} + 1 = \frac{10}{3}

\frac{7}{3} + 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= \frac{7}{3} + \frac{1 \cdot 3}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 + 1 \cdot 3}{3}

7 + 1 \cdot 3 = 10

7 + 1 \cdot 3

Multiply the numbers:

1 \cdot 3 = 3

= 7 + 3

Add the numbers:

7 + 3 = 10

= 10

= \frac{10}{3}

= 2^{\frac{10}{3}}

= \frac{3}{2 ^{\frac{10}{3}} v}

u = \frac{3}{2 ^{\frac{10}{3}} v}

u = \frac{3}{2 ^{\frac{10}{3}} v}

u = \frac{3}{2 ^{\frac{10}{3}} v}

Plug the solutions

u = \frac{3}{2 ^{\frac{10}{3}} v}

into

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

For

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

, subsitute

u

with

\frac{3}{2 ^{\frac{10}{3}} v} : v \approx 0.54556 \dots, v \approx - 0.54556 \dots

For

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

, subsitute

u

with

\frac{3}{2 ^{\frac{10}{3}} v}

(\frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Solve

(\frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} : v \approx 0.54556 \dots, v \approx - 0.54556 \dots

(\frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Multiply by LCM

(\frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Simplify

(\frac{3}{2 ^{\frac{10}{3}} v})^{2} : \frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

(\frac{3}{2 ^{\frac{10}{3}} v})^{2}

\frac{3}{2 ^{\frac{10}{3}} v}

2^{\frac{10}{3}}

2^{\frac{10}{3}} = 2^{3 + \frac{1}{3}}

= 2^{3 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{3} \cdot 2^{\frac{1}{3}}

Refine

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

(2^{3})^{2} : 2^{6}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= 2^{6}

Apply radical rule:

= (2^{\frac{1}{3}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{3} \cdot 2}

\frac{1}{3} \cdot 2 = \frac{2}{3}

\frac{1}{3} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{3}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2}{3}

= 2^{\frac{2}{3}}

= \frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

2^{6} \cdot 2^{\frac{2}{3}} v^{2} = 2^{6 + \frac{2}{3}} v^{2}

2^{6} \cdot 2^{\frac{2}{3}} v^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{6} \cdot 2^{\frac{2}{3}} = 2^{6 + \frac{2}{3}}

= 2^{6 + \frac{2}{3}} v^{2}

= \frac{3}{2 ^{\frac{2}{3} + 6} v ^{2}}

2^{6 + \frac{2}{3}} = 2^{6} \cdot 2^{\frac{2}{3}}

2^{6 + \frac{2}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{6} \cdot 2^{\frac{2}{3}}

= \frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Find Least Common Multiplier of

2^{6 + \frac{2}{3}} v^{2}, 8 : 64 \cdot 2^{\frac{2}{3}} v^{2}

2^{6 + \frac{2}{3}} v^{2}, 8

Lowest Common Multiplier (LCM)

Least Common Multiplier of

64, 8 : 64

64, 8

Least Common Multiplier (LCM)

Prime factorization of

64 : 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

64

64

divides by

264 = 32 \cdot 2

= 2 \cdot 32

32

divides by

232 = 16 \cdot 2

= 2 \cdot 2 \cdot 16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

Prime factorization of

8 : 2 \cdot 2 \cdot 2

8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2

Multiply each factor the greatest number of times it occurs in either

64

8

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

Multiply the numbers:

2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 = 64

= 64

Compute an expression comprised of factors that appear either in

64 \cdot 2^{\frac{2}{3}} v^{2}

8

= 64 \cdot 2^{\frac{2}{3}} v^{2}

Multiply by LCM=

64 \cdot 2^{\frac{2}{3}} v^{2}

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} - v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Simplify

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} - v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Simplify

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} : 3

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 64 \cdot 2 ^{\frac{2}{3}} v ^{2}}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

Cancel the common factor:

2^{\frac{2}{3}}

= \frac{3 \cdot 64 v ^{2}}{2 ^{6} v ^{2}}

Cancel the common factor:

v^{2}

= \frac{3 \cdot 64}{2 ^{6}}

Multiply the numbers:

3 \cdot 64 = 192

= \frac{192}{2 ^{6}}

Factor

192 : 2^{6} \cdot 3

Factor

192 = 2^{6} \cdot 3

= \frac{2 ^{6} \cdot 3}{2 ^{6}}

Cancel the common factor:

2^{6}

= 3

Simplify

- v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} : - 64 \cdot 2^{\frac{2}{3}} v^{4}

- v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

v^{2} v^{2} = v^{2 + 2}

= - 64 \cdot 2^{\frac{2}{3}} v^{2 + 2}

Add the numbers:

2 + 2 = 4

= - 64 \cdot 2^{\frac{2}{3}} v^{4}

Simplify

- \frac{2 ^{\frac{2}{3}}}{8} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 ^{\frac{2}{3}} \cdot 64 \cdot 2 ^{\frac{2}{3}} v ^{2}}{8}

2^{\frac{2}{3}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} = 64 \cdot 2^{2 \cdot \frac{2}{3}} v^{2}

2^{\frac{2}{3}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{2}{3}} \cdot 2^{\frac{2}{3}} = 2^{\frac{2}{3} + \frac{2}{3}}

= 64 \cdot 2^{\frac{2}{3} + \frac{2}{3}} v^{2}

Add similar elements:

\frac{2}{3} + \frac{2}{3} = 2 \cdot \frac{2}{3}

= 64 \cdot 2^{2 \cdot \frac{2}{3}} v^{2}

= - \frac{64 \cdot 2 ^{2 \cdot \frac{2}{3}} v ^{2}}{8}

Divide the numbers:

\frac{64}{8} = 8

= - 8 \cdot 2^{2 \cdot \frac{2}{3}} v^{2}

2^{2 \cdot \frac{2}{3}}

Multiply

2 \cdot \frac{2}{3} : \frac{4}{3}

2 \cdot \frac{2}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 2}{3}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{4}{3}

= 2^{\frac{4}{3}}

2^{\frac{4}{3}} = 2^{1 + \frac{1}{3}}

= 2^{1 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{1} \cdot 2^{\frac{1}{3}}

Refine

Multiply the numbers:

8 \cdot 2 = 16

Solve

Move

to the left side

Add

to both sides

Simplify

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

Find one solution for

- 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3 = 0

using Newton-Raphson:

v \approx 0.54556 \dots

- 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3 = 0

Newton-Raphson Approximation Definition

f (v) = - 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3

Find

f^{^{'}} (v) : - 406.37466 \dots v^{3} + 40.31747 \dots v

\frac{d}{d v} (- 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d v} (101.59366 \dots v^{4}) + \frac{d}{d v} (20.15873 \dots v^{2}) + \frac{d}{d v} (3)

\frac{d}{d v} (101.59366 \dots v^{4}) = 406.37466 \dots v^{3}

\frac{d}{d v} (101.59366 \dots v^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 101.59366 \dots \frac{d}{d v} (v^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 101.59366 \dots \cdot 4 v^{4 - 1}

Simplify

= 406.37466 \dots v^{3}

\frac{d}{d v} (20.15873 \dots v^{2}) = 40.31747 \dots v

\frac{d}{d v} (20.15873 \dots v^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 20.15873 \dots \frac{d}{d v} (v^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 20.15873 \dots \cdot 2 v^{2 - 1}

Simplify

= 40.31747 \dots v

\frac{d}{d v} (3) = 0

\frac{d}{d v} (3)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

= - 406.37466 \dots v^{3} + 40.31747 \dots v + 0

Simplify

= - 406.37466 \dots v^{3} + 40.31747 \dots v

Let

v_{0} = 1

Compute

v_{n + 1}

until

Δ v_{n + 1} < 0.000001

v_{1} = 0.78573 \dots : Δ v_{1} = 0.21426 \dots

f (v_{0}) = - 101.59366 \dots \cdot 1^{4} + 20.15873 \dots \cdot 1^{2} + 3 = - 78.43493 \dots

f^{^{'}} (v_{0}) = - 406.37466 \dots \cdot 1^{3} + 40.31747 \dots \cdot 1 = - 366.05719 \dots

v_{1} = 0.78573 \dots

Δ v_{1} = ∣ 0.78573 \dots - 1 ∣ = 0.21426 \dots

Δ v_{1} = 0.21426 \dots

v_{2} = 0.64504 \dots : Δ v_{2} = 0.14068 \dots

f (v_{1}) = - 101.59366 \dots \cdot 0.78573 \dots^{4} + 20.15873 \dots \cdot 0.78573 \dots^{2} + 3 = - 23.27682 \dots

f^{^{'}} (v_{1}) = - 406.37466 \dots \cdot 0.78573 \dots^{3} + 40.31747 \dots \cdot 0.78573 \dots = - 165.44887 \dots

v_{2} = 0.64504 \dots

Δ v_{2} = ∣ 0.64504 \dots - 0.78573 \dots ∣ = 0.14068 \dots

Δ v_{2} = 0.14068 \dots

v_{3} = 0.57039 \dots : Δ v_{3} = 0.07465 \dots

f (v_{2}) = - 101.59366 \dots \cdot 0.64504 \dots^{4} + 20.15873 \dots \cdot 0.64504 \dots^{2} + 3 = - 6.20040 \dots

f^{^{'}} (v_{2}) = - 406.37466 \dots \cdot 0.64504 \dots^{3} + 40.31747 \dots \cdot 0.64504 \dots = - 83.05958 \dots

v_{3} = 0.57039 \dots

Δ v_{3} = ∣ 0.57039 \dots - 0.64504 \dots ∣ = 0.07465 \dots

Δ v_{3} = 0.07465 \dots

v_{4} = 0.54759 \dots : Δ v_{4} = 0.02280 \dots

f (v_{3}) = - 101.59366 \dots \cdot 0.57039 \dots^{4} + 20.15873 \dots \cdot 0.57039 \dots^{2} + 3 = - 1.19513 \dots

f^{^{'}} (v_{3}) = - 406.37466 \dots \cdot 0.57039 \dots^{3} + 40.31747 \dots \cdot 0.57039 \dots = - 52.41610 \dots

v_{4} = 0.54759 \dots

Δ v_{4} = ∣ 0.54759 \dots - 0.57039 \dots ∣ = 0.02280 \dots

Δ v_{4} = 0.02280 \dots

v_{5} = 0.54557 \dots : Δ v_{5} = 0.00201 \dots

f (v_{4}) = - 101.59366 \dots \cdot 0.54759 \dots^{4} + 20.15873 \dots \cdot 0.54759 \dots^{2} + 3 = - 0.08990 \dots

f^{^{'}} (v_{4}) = - 406.37466 \dots \cdot 0.54759 \dots^{3} + 40.31747 \dots \cdot 0.54759 \dots = - 44.64836 \dots

v_{5} = 0.54557 \dots

Δ v_{5} = ∣ 0.54557 \dots - 0.54759 \dots ∣ = 0.00201 \dots

Δ v_{5} = 0.00201 \dots

v_{6} = 0.54556 \dots : Δ v_{6} = 0.00001 \dots

f (v_{5}) = - 101.59366 \dots \cdot 0.54557 \dots^{4} + 20.15873 \dots \cdot 0.54557 \dots^{2} + 3 = - 0.00065 \dots

f^{^{'}} (v_{5}) = - 406.37466 \dots \cdot 0.54557 \dots^{3} + 40.31747 \dots \cdot 0.54557 \dots = - 43.99616 \dots

v_{6} = 0.54556 \dots

Δ v_{6} = ∣ 0.54556 \dots - 0.54557 \dots ∣ = 0.00001 \dots

Δ v_{6} = 0.00001 \dots

v_{7} = 0.54556 \dots : Δ v_{7} = 8.18838 E - 10

f (v_{6}) = - 101.59366 \dots \cdot 0.54556 \dots^{4} + 20.15873 \dots \cdot 0.54556 \dots^{2} + 3 = - 3.60218 E - 8

f^{^{'}} (v_{6}) = - 406.37466 \dots \cdot 0.54556 \dots^{3} + 40.31747 \dots \cdot 0.54556 \dots = - 43.99134 \dots

v_{7} = 0.54556 \dots

Δ v_{7} = ∣ 0.54556 \dots - 0.54556 \dots ∣ = 8.18838 E - 10

Δ v_{7} = 8.18838 E - 10

v \approx 0.54556 \dots

Apply long division:

- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots \approx 0

Find one solution for

- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots = 0

using Newton-Raphson:

v \approx - 0.54556 \dots

- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots = 0

Newton-Raphson Approximation Definition

f (v) = - 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots

Find

f^{^{'}} (v) : - 304.78100 \dots v^{2} - 110.85125 \dots v - 10.07936 \dots

\frac{d}{d v} (- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d v} (101.59366 \dots v^{3}) - \frac{d}{d v} (55.42562 \dots v^{2}) - \frac{d}{d v} (10.07936 \dots v) - \frac{d}{d v} (5.49891 \dots)

\frac{d}{d v} (101.59366 \dots v^{3}) = 304.78100 \dots v^{2}

\frac{d}{d v} (101.59366 \dots v^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 101.59366 \dots \frac{d}{d v} (v^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 101.59366 \dots \cdot 3 v^{3 - 1}

Simplify

= 304.78100 \dots v^{2}

\frac{d}{d v} (55.42562 \dots v^{2}) = 110.85125 \dots v

\frac{d}{d v} (55.42562 \dots v^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 55.42562 \dots \frac{d}{d v} (v^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 55.42562 \dots \cdot 2 v^{2 - 1}

Simplify

= 110.85125 \dots v

\frac{d}{d v} (10.07936 \dots v) = 10.07936 \dots

\frac{d}{d v} (10.07936 \dots v)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10.07936 \dots \frac{d v}{d v}

Apply the common derivative:

\frac{d v}{d v} = 1

= 10.07936 \dots \cdot 1

Simplify

= 10.07936 \dots

\frac{d}{d v} (5.49891 \dots) = 0

\frac{d}{d v} (5.49891 \dots)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

= - 304.78100 \dots v^{2} - 110.85125 \dots v - 10.07936 \dots - 0

Simplify

= - 304.78100 \dots v^{2} - 110.85125 \dots v - 10.07936 \dots

Let

v_{0} = - 1

Compute

v_{n + 1}

until

Δ v_{n + 1} < 0.000001

v_{1} = - 0.75124 \dots : Δ v_{1} = 0.24875 \dots

f (v_{0}) = - 101.59366 \dots (- 1)^{3} - 55.42562 \dots (- 1)^{2} - 10.07936 \dots (- 1) - 5.49891 \dots = 50.74849 \dots

f^{^{'}} (v_{0}) = - 304.78100 \dots (- 1)^{2} - 110.85125 \dots (- 1) - 10.07936 \dots = - 204.00911 \dots

v_{1} = - 0.75124 \dots

Δ v_{1} = ∣ - 0.75124 \dots - (- 1) ∣ = 0.24875 \dots

Δ v_{1} = 0.24875 \dots

v_{2} = - 0.61091 \dots : Δ v_{2} = 0.14032 \dots

f (v_{1}) = - 101.59366 \dots (- 0.75124 \dots)^{3} - 55.42562 \dots (- 0.75124 \dots)^{2} - 10.07936 \dots (- 0.75124 \dots) - 5.49891 \dots = 13.86617 \dots

f^{^{'}} (v_{1}) = - 304.78100 \dots (- 0.75124 \dots)^{2} - 110.85125 \dots (- 0.75124 \dots) - 10.07936 \dots = - 98.81153 \dots

v_{2} = - 0.61091 \dots

Δ v_{2} = ∣ - 0.61091 \dots - (- 0.75124 \dots) ∣ = 0.14032 \dots

Δ v_{2} = 0.14032 \dots

v_{3} = - 0.55501 \dots : Δ v_{3} = 0.05590 \dots

f (v_{2}) = - 101.59366 \dots (- 0.61091 \dots)^{3} - 55.42562 \dots (- 0.61091 \dots)^{2} - 10.07936 \dots (- 0.61091 \dots) - 5.49891 \dots = 3.13665 \dots

f^{^{'}} (v_{2}) = - 304.78100 \dots (- 0.61091 \dots)^{2} - 110.85125 \dots (- 0.61091 \dots) - 10.07936 \dots = - 56.10803 \dots

v_{3} = - 0.55501 \dots

Δ v_{3} = ∣ - 0.55501 \dots - (- 0.61091 \dots) ∣ = 0.05590 \dots

Δ v_{3} = 0.05590 \dots

v_{4} = - 0.54579 \dots : Δ v_{4} = 0.00921 \dots

f (v_{3}) = - 101.59366 \dots (- 0.55501 \dots)^{3} - 55.42562 \dots (- 0.55501 \dots)^{2} - 10.07936 \dots (- 0.55501 \dots) - 5.49891 \dots = 0.39093 \dots

f^{^{'}} (v_{3}) = - 304.78100 \dots (- 0.55501 \dots)^{2} - 110.85125 \dots (- 0.55501 \dots) - 10.07936 \dots = - 42.43951 \dots

v_{4} = - 0.54579 \dots

Δ v_{4} = ∣ - 0.54579 \dots - (- 0.55501 \dots) ∣ = 0.00921 \dots

Δ v_{4} = 0.00921 \dots

v_{5} = - 0.54556 \dots : Δ v_{5} = 0.00023 \dots

f (v_{4}) = - 101.59366 \dots (- 0.54579 \dots)^{3} - 55.42562 \dots (- 0.54579 \dots)^{2} - 10.07936 \dots (- 0.54579 \dots) - 5.49891 \dots = 0.00957 \dots

f^{^{'}} (v_{4}) = - 304.78100 \dots (- 0.54579 \dots)^{2} - 110.85125 \dots (- 0.54579 \dots) - 10.07936 \dots = - 40.37008 \dots

v_{5} = - 0.54556 \dots

Δ v_{5} = ∣ - 0.54556 \dots - (- 0.54579 \dots) ∣ = 0.00023 \dots

Δ v_{5} = 0.00023 \dots

v_{6} = - 0.54556 \dots : Δ v_{6} = 1.54611 E - 7

f (v_{5}) = - 101.59366 \dots (- 0.54556 \dots)^{3} - 55.42562 \dots (- 0.54556 \dots)^{2} - 10.07936 \dots (- 0.54556 \dots) - 5.49891 \dots = 6.23352 E - 6

f^{^{'}} (v_{5}) = - 304.78100 \dots (- 0.54556 \dots)^{2} - 110.85125 \dots (- 0.54556 \dots) - 10.07936 \dots = - 40.31750 \dots

v_{6} = - 0.54556 \dots

Δ v_{6} = ∣ - 0.54556 \dots - (- 0.54556 \dots) ∣ = 1.54611 E - 7

Δ v_{6} = 1.54611 E - 7

v \approx - 0.54556 \dots

Apply long division:

\frac{- 101.59366 \dots v ^{3} - 55.42562 \dots v ^{2} - 10.07936 \dots v - 5.49891 \dots}{v + 0.54556 \dots} = - 101.59366 \dots v^{2} - 10.07936 \dots

- 101.59366 \dots v^{2} - 10.07936 \dots \approx 0

Find one solution for

- 101.59366 \dots v^{2} - 10.07936 \dots = 0

using Newton-Raphson:

No Solution for

v \in R

- 101.59366 \dots v^{2} - 10.07936 \dots = 0

Newton-Raphson Approximation Definition

f (v) = - 101.59366 \dots v^{2} - 10.07936 \dots

Find

f^{^{'}} (v) : - 203.18733 \dots v

\frac{d}{d v} (- 101.59366 \dots v^{2} - 10.07936 \dots)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d v} (101.59366 \dots v^{2}) - \frac{d}{d v} (10.07936 \dots)

\frac{d}{d v} (101.59366 \dots v^{2}) = 203.18733 \dots v

\frac{d}{d v} (101.59366 \dots v^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 101.59366 \dots \frac{d}{d v} (v^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 101.59366 \dots \cdot 2 v^{2 - 1}

Simplify

= 203.18733 \dots v

\frac{d}{d v} (10.07936 \dots) = 0

\frac{d}{d v} (10.07936 \dots)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

= - 203.18733 \dots v - 0

Simplify

= - 203.18733 \dots v

Let

v_{0} = - 1

Compute

v_{n + 1}

until

Δ v_{n + 1} < 0.000001

v_{1} = - 0.45039 \dots : Δ v_{1} = 0.54960 \dots

f (v_{0}) = - 101.59366 \dots (- 1)^{2} - 10.07936 \dots = - 111.67303 \dots

f^{^{'}} (v_{0}) = - 203.18733 \dots (- 1) = 203.18733 \dots

v_{1} = - 0.45039 \dots

Δ v_{1} = ∣ - 0.45039 \dots - (- 1) ∣ = 0.54960 \dots

Δ v_{1} = 0.54960 \dots

v_{2} = - 0.11505 \dots : Δ v_{2} = 0.33533 \dots

f (v_{1}) = - 101.59366 \dots (- 0.45039 \dots)^{2} - 10.07936 \dots = - 30.68810 \dots

f^{^{'}} (v_{1}) = - 203.18733 \dots (- 0.45039 \dots) = 91.51429 \dots

v_{2} = - 0.11505 \dots

Δ v_{2} = ∣ - 0.11505 \dots - (- 0.45039 \dots) ∣ = 0.33533 \dots

Δ v_{2} = 0.33533 \dots

v_{3} = 0.37361 \dots : Δ v_{3} = 0.48867 \dots

f (v_{2}) = - 101.59366 \dots (- 0.11505 \dots)^{2} - 10.07936 \dots = - 11.42427 \dots

f^{^{'}} (v_{2}) = - 203.18733 \dots (- 0.11505 \dots) = 23.37813 \dots

v_{3} = 0.37361 \dots

Δ v_{3} = ∣ 0.37361 \dots - (- 0.11505 \dots) ∣ = 0.48867 \dots

Δ v_{3} = 0.48867 \dots

v_{4} = 0.05403 \dots : Δ v_{4} = 0.31958 \dots

f (v_{3}) = - 101.59366 \dots \cdot 0.37361 \dots^{2} - 10.07936 \dots = - 24.26076 \dots

f^{^{'}} (v_{3}) = - 203.18733 \dots \cdot 0.37361 \dots = - 75.91416 \dots

v_{4} = 0.05403 \dots

Δ v_{4} = ∣ 0.05403 \dots - 0.37361 \dots ∣ = 0.31958 \dots

Δ v_{4} = 0.31958 \dots

v_{5} = - 0.89102 \dots : Δ v_{5} = 0.94505 \dots

f (v_{4}) = - 101.59366 \dots \cdot 0.05403 \dots^{2} - 10.07936 \dots = - 10.37600 \dots

f^{^{'}} (v_{4}) = - 203.18733 \dots \cdot 0.05403 \dots = - 10.97924 \dots

v_{5} = - 0.89102 \dots

Δ v_{5} = ∣ - 0.89102 \dots - 0.05403 \dots ∣ = 0.94505 \dots

Δ v_{5} = 0.94505 \dots

v_{6} = - 0.38983 \dots : Δ v_{6} = 0.50118 \dots

f (v_{5}) = - 101.59366 \dots (- 0.89102 \dots)^{2} - 10.07936 \dots = - 90.73642 \dots

f^{^{'}} (v_{5}) = - 203.18733 \dots (- 0.89102 \dots) = 181.04414 \dots

v_{6} = - 0.38983 \dots

Δ v_{6} = ∣ - 0.38983 \dots - (- 0.89102 \dots) ∣ = 0.50118 \dots

Δ v_{6} = 0.50118 \dots

v_{7} = - 0.06766 \dots : Δ v_{7} = 0.32216 \dots

f (v_{6}) = - 101.59366 \dots (- 0.38983 \dots)^{2} - 10.07936 \dots = - 25.51884 \dots

f^{^{'}} (v_{6}) = - 203.18733 \dots (- 0.38983 \dots) = 79.20991 \dots

v_{7} = - 0.06766 \dots

Δ v_{7} = ∣ - 0.06766 \dots - (- 0.38983 \dots) ∣ = 0.32216 \dots

Δ v_{7} = 0.32216 \dots

v_{8} = 0.69923 \dots : Δ v_{8} = 0.76690 \dots

f (v_{7}) = - 101.59366 \dots (- 0.06766 \dots)^{2} - 10.07936 \dots = - 10.54458 \dots

f^{^{'}} (v_{7}) = - 203.18733 \dots (- 0.06766 \dots) = 13.74960 \dots

v_{8} = 0.69923 \dots

Δ v_{8} = ∣ 0.69923 \dots - (- 0.06766 \dots) ∣ = 0.76690 \dots

Δ v_{8} = 0.76690 \dots

v_{9} = 0.27867 \dots : Δ v_{9} = 0.42055 \dots

f (v_{8}) = - 101.59366 \dots \cdot 0.69923 \dots^{2} - 10.07936 \dots = - 59.75094 \dots

f^{^{'}} (v_{8}) = - 203.18733 \dots \cdot 0.69923 \dots = - 142.07487 \dots

v_{9} = 0.27867 \dots

Δ v_{9} = ∣ 0.27867 \dots - 0.69923 \dots ∣ = 0.42055 \dots

Δ v_{9} = 0.42055 \dots

v_{10} = - 0.03867 \dots : Δ v_{10} = 0.31734 \dots

f (v_{9}) = - 101.59366 \dots \cdot 0.27867 \dots^{2} - 10.07936 \dots = - 17.96890 \dots

f^{^{'}} (v_{9}) = - 203.18733 \dots \cdot 0.27867 \dots = - 56.62250 \dots

v_{10} = - 0.03867 \dots

Δ v_{10} = ∣ - 0.03867 \dots - 0.27867 \dots ∣ = 0.31734 \dots

Δ v_{10} = 0.31734 \dots

v_{11} = 1.26333 \dots : Δ v_{11} = 1.30200 \dots

f (v_{10}) = - 101.59366 \dots (- 0.03867 \dots)^{2} - 10.07936 \dots = - 10.23132 \dots

f^{^{'}} (v_{10}) = - 203.18733 \dots (- 0.03867 \dots) = 7.85811 \dots

v_{11} = 1.26333 \dots

Δ v_{11} = ∣ 1.26333 \dots - (- 0.03867 \dots) ∣ = 1.30200 \dots

Δ v_{11} = 1.30200 \dots

Cannot find solution

The solutions are

v \approx 0.54556 \dots, v \approx - 0.54556 \dots

v \approx 0.54556 \dots, v \approx - 0.54556 \dots

Verify Solutions

Find undefined (singularity) points:

v = 0

Take the denominator(s) of

(\frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2}

and compare to zero

Solve

2^{\frac{10}{3}} v = 0 : v = 0

2^{\frac{10}{3}} v = 0

Divide both sides by

2^{\frac{10}{3}}

2^{\frac{10}{3}} v = 0

Divide both sides by

2^{\frac{10}{3}}

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}} = \frac{0}{2 ^{\frac{10}{3}}}

Simplify

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}} = \frac{0}{2 ^{\frac{10}{3}}}

Simplify

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}} : v

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}}

Cancel the common factor:

2^{\frac{10}{3}}

= v

Simplify

\frac{0}{2 ^{\frac{10}{3}}} : 0

\frac{0}{2 ^{\frac{10}{3}}}

Apply rule

\frac{0}{a} = 0

a \neq = 0

= 0

v = 0

v = 0

v = 0

The following points are undefined

v = 0

Combine undefined points with solutions:

v \approx 0.54556 \dots, v \approx - 0.54556 \dots

Plug the solutions

v = 0.54556 \dots, v = - 0.54556 \dots

into

2 uv = \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

For

2 uv = \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

For

2 uv = \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

0.54556 \dots

2 u \cdot 0.54556 \dots = \frac{2 ^{\frac{2}{3}} 3}{8}

Solve

2 u \cdot 0.54556 \dots = \frac{2 ^{\frac{2}{3}} 3}{8}

Simplify

\frac{2 ^{\frac{2}{3}} 3}{8} : \frac{3}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}} 3}{8}

Factor the number:

8 = 2^{3}

= \frac{2 ^{\frac{2}{3}} 3}{2 ^{3}}

Simplify

\frac{2 ^{\frac{2}{3}}}{2 ^{3}} : \frac{1}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

= \frac{1}{2 ^{3 - \frac{2}{3}}}

3 - \frac{2}{3} = \frac{7}{3}

3 - \frac{2}{3}

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= \frac{3 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 3 - 2}{3}

3 \cdot 3 - 2 = 7

3 \cdot 3 - 2

Multiply the numbers:

3 \cdot 3 = 9

= 9 - 2

Subtract the numbers:

9 - 2 = 7

= 7

= \frac{7}{3}

= \frac{1}{2 ^{\frac{7}{3}}}

= \frac{3}{2 ^{\frac{7}{3}}}

2 u \cdot 0.54556 \dots = \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 \cdot 0.54556 \dots

2 u \cdot 0.54556 \dots = \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 \cdot 0.54556 \dots

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots} = \frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 \cdot 0.54556 \dots}

Simplify

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots} = \frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 \cdot 0.54556 \dots}

Simplify

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots} : u

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots}

Cancel the common factor:

2

= \frac{u \cdot 0.54556 \dots}{0.54556 \dots}

Cancel the common factor:

0.54556 \dots

= u

Simplify

\frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 \cdot 0.54556 \dots}

Multiply the numbers:

2 \cdot 0.54556 \dots = 1.09112 \dots

= \frac{\frac{3}{2 ^{\frac{7}{3}}}}{1.09112 \dots}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 ^{\frac{7}{3}} \cdot 1.09112 \dots}

2^{\frac{7}{3}}

2^{\frac{7}{3}} = 2^{2 + \frac{1}{3}}

= 2^{2 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{2} \cdot 2^{\frac{1}{3}}

Refine

For

2 uv = \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

For

2 uv = \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

- 0.54556 \dots

2 u (- 0.54556 \dots) = \frac{2 ^{\frac{2}{3}} 3}{8}

Solve

2 u (- 0.54556 \dots) = \frac{2 ^{\frac{2}{3}} 3}{8}

Simplify

\frac{2 ^{\frac{2}{3}} 3}{8} : \frac{3}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}} 3}{8}

Factor the number:

8 = 2^{3}

= \frac{2 ^{\frac{2}{3}} 3}{2 ^{3}}

Simplify

\frac{2 ^{\frac{2}{3}}}{2 ^{3}} : \frac{1}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

= \frac{1}{2 ^{3 - \frac{2}{3}}}

3 - \frac{2}{3} = \frac{7}{3}

3 - \frac{2}{3}

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= \frac{3 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 3 - 2}{3}

3 \cdot 3 - 2 = 7

3 \cdot 3 - 2

Multiply the numbers:

3 \cdot 3 = 9

= 9 - 2

Subtract the numbers:

9 - 2 = 7

= 7

= \frac{7}{3}

= \frac{1}{2 ^{\frac{7}{3}}}

= \frac{3}{2 ^{\frac{7}{3}}}

2 u (- 0.54556 \dots) = \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 (- 0.54556 \dots)

2 u (- 0.54556 \dots) = \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 (- 0.54556 \dots)

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )} = \frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 ( - 0.54556 \dots )}

Simplify

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )} = \frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 ( - 0.54556 \dots )}

Simplify

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )} : u

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )}

Multiply the numbers:

2 (- 0.54556 \dots) = - 1.09112 \dots

= \frac{- 1.09112 \dots u}{- 1.09112 \dots}

Cancel the common factor:

- 1.09112 \dots

= u

Simplify

\frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 ( - 0.54556 \dots )}

Remove parentheses:

(- a) = - a

= \frac{\frac{3}{2 ^{\frac{7}{3}}}}{- 2 \cdot 0.54556 \dots}

Multiply the numbers:

2 \cdot 0.54556 \dots = 1.09112 \dots

= \frac{\frac{3}{2 ^{\frac{7}{3}}}}{- 1.09112 \dots}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{3}{2 ^{\frac{7}{3}}}}{1.09112 \dots}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2 ^{\frac{7}{3}}}}{1.09112 \dots} = \frac{3}{2 ^{\frac{7}{3}} \cdot 1.09112 \dots}

= - \frac{3}{2 ^{\frac{7}{3}} \cdot 1.09112 \dots}

2^{\frac{7}{3}}

2^{\frac{7}{3}} = 2^{2 + \frac{1}{3}}

= 2^{2 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{2} \cdot 2^{\frac{1}{3}}

Refine

Verify solutions by plugging them into the original equations

Check the solutions by plugging them into

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Remove the ones that don't agree with the equation.

Check the solution

True

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Plug in

Refine

True

Check the solution

True

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Plug in

Refine

True

Check the solutions by plugging them into

2 uv = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Remove the ones that don't agree with the equation.

Check the solution

True

2 uv = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Plug in

Refine

\frac{3 \cdot 2 ^{\frac{2}{3}} \cdot 0.54556 \dots}{4.36449 \dots} = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

True

Check the solution

True

2 uv = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Plug in

Refine

\frac{3 \cdot 2 ^{\frac{2}{3}} \cdot 0.54556 \dots}{4.36449 \dots} = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

True

Therefore, the final solutions for

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}, 2 uv = \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

are

Substitute back

w = u + v i

Solve

Substitute

w = u + v i

Expand

(u + v i)^{2} : (u^{2} - v^{2}) + 2 i uv

(u + v i)^{2}

= (u + i v)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = u, b = v i

= u^{2} + 2 uv i + (v i)^{2}

(v i)^{2} = - v^{2}

(v i)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= i^{2} v^{2}

i^{2} = - 1

i^{2}

Apply imaginary number rule:

i^{2} = - 1

= - 1

= (- 1) v^{2}

Refine

= - v^{2}

= u^{2} + 2 i uv - v^{2}

Rewrite

u^{2} + 2 i uv - v^{2}

in standard complex form:

(u^{2} - v^{2}) + 2 uv i

u^{2} + 2 i uv - v^{2}

Group the real part and the imaginary part of the complex number

= (u^{2} - v^{2}) + 2 uv i

= (u^{2} - v^{2}) + 2 uv i

Expand

Apply radical rule:

assuming

a \geq 0, b \geq 0

Prime factorization of

16 : 2^{4}

16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2

2

is a prime number, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2

= 2^{4}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

Apply radical rule:

Apply rule

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

1 \cdot (- 1 - 3 i) = - 1 - 3 i

1 \cdot (- 1 - 3 i)

Multiply:

1 \cdot (- 1 - 3 i) = (- 1 - 3 i)

= (- 1 - 3 i)

Remove parentheses:

(- a) = - a

= - 1 - 3 i

Multiply the numbers:

2 \cdot 2 = 4

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

Rewrite

in standard complex form:

- \frac{2 ^{\frac{2}{3}}}{8} - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8} i

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4 \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

1 \cdot 2^{\frac{2}{3}} = 2^{\frac{2}{3}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4 \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= - \frac{2 ^{\frac{2}{3}}}{8}

= - \frac{2 ^{\frac{2}{3}}}{8} - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8} i

= - \frac{2 ^{\frac{2}{3}}}{8} - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8} i

(u^{2} - v^{2}) + 2 i uv = - \frac{2 ^{\frac{2}{3}}}{8} - i \frac{2 ^{\frac{2}{3}} 3}{8}

(u^{2} - v^{2}) + 2 i uv = - \frac{2 ^{\frac{2}{3}}}{8} - i \frac{2 ^{\frac{2}{3}} 3}{8}

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} 2 uv = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}]

[u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} 2 uv = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}]

Isolate

u

for

2 uv = - \frac{2 ^{\frac{2}{3}} \cdot 3}{8} : u = - \frac{3}{2 ^{\frac{10}{3}} v}

2 uv = - \frac{2 ^{\frac{2}{3}} 3}{8}

Simplify

- \frac{2 ^{\frac{2}{3}} 3}{8} : - \frac{3}{2 ^{\frac{7}{3}}}

- \frac{2 ^{\frac{2}{3}} 3}{8}

Factor the number:

8 = 2^{3}

= - \frac{2 ^{\frac{2}{3}} 3}{2 ^{3}}

Simplify

\frac{2 ^{\frac{2}{3}}}{2 ^{3}} : \frac{1}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

= \frac{1}{2 ^{3 - \frac{2}{3}}}

3 - \frac{2}{3} = \frac{7}{3}

3 - \frac{2}{3}

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= \frac{3 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 3 - 2}{3}

3 \cdot 3 - 2 = 7

3 \cdot 3 - 2

Multiply the numbers:

3 \cdot 3 = 9

= 9 - 2

Subtract the numbers:

9 - 2 = 7

= 7

= \frac{7}{3}

= \frac{1}{2 ^{\frac{7}{3}}}

= - \frac{3}{2 ^{\frac{7}{3}}}

2 uv = - \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 v

2 uv = - \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 v

\frac{2 uv}{2 v} = \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 v}

Simplify

\frac{2 uv}{2 v} = \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 v}

Simplify

\frac{2 uv}{2 v} : u

\frac{2 uv}{2 v}

Cancel the common factor:

2

= \frac{uv}{v}

Cancel the common factor:

v

= u

Simplify

\frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 v} : - \frac{3}{2 ^{\frac{10}{3}} v}

\frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 v}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 v}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

\frac{\frac{3}{2 ^{\frac{7}{3}}}}{2 v} = \frac{3}{2 ^{\frac{7}{3}} \cdot 2 v}

= - \frac{3}{2 ^{\frac{7}{3}} \cdot 2 v}

2^{\frac{7}{3}} \cdot 2 = 2^{\frac{10}{3}}

2^{\frac{7}{3}} \cdot 2

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{7}{3}} \cdot 2 = 2^{\frac{7}{3} + 1}

= 2^{\frac{7}{3} + 1}

\frac{7}{3} + 1 = \frac{10}{3}

\frac{7}{3} + 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= \frac{7}{3} + \frac{1 \cdot 3}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 + 1 \cdot 3}{3}

7 + 1 \cdot 3 = 10

7 + 1 \cdot 3

Multiply the numbers:

1 \cdot 3 = 3

= 7 + 3

Add the numbers:

7 + 3 = 10

= 10

= \frac{10}{3}

= 2^{\frac{10}{3}}

= - \frac{3}{2 ^{\frac{10}{3}} v}

u = - \frac{3}{2 ^{\frac{10}{3}} v}

u = - \frac{3}{2 ^{\frac{10}{3}} v}

u = - \frac{3}{2 ^{\frac{10}{3}} v}

Plug the solutions

u = - \frac{3}{2 ^{\frac{10}{3}} v}

into

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

For

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

, subsitute

u

with

- \frac{3}{2 ^{\frac{10}{3}} v} : v \approx 0.54556 \dots, v \approx - 0.54556 \dots

For

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

, subsitute

u

with

- \frac{3}{2 ^{\frac{10}{3}} v}

(- \frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Solve

(- \frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} : v \approx 0.54556 \dots, v \approx - 0.54556 \dots

(- \frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Multiply by LCM

(- \frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Simplify

(- \frac{3}{2 ^{\frac{10}{3}} v})^{2} : \frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

(- \frac{3}{2 ^{\frac{10}{3}} v})^{2}

\frac{3}{2 ^{\frac{10}{3}} v}

2^{\frac{10}{3}}

2^{\frac{10}{3}} = 2^{3 + \frac{1}{3}}

= 2^{3 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{3} \cdot 2^{\frac{1}{3}}

Refine

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

(2^{3})^{2} : 2^{6}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= 2^{6}

Apply radical rule:

= (2^{\frac{1}{3}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{3} \cdot 2}

\frac{1}{3} \cdot 2 = \frac{2}{3}

\frac{1}{3} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{3}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2}{3}

= 2^{\frac{2}{3}}

= \frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

2^{6} \cdot 2^{\frac{2}{3}} v^{2} = 2^{6 + \frac{2}{3}} v^{2}

2^{6} \cdot 2^{\frac{2}{3}} v^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{6} \cdot 2^{\frac{2}{3}} = 2^{6 + \frac{2}{3}}

= 2^{6 + \frac{2}{3}} v^{2}

= \frac{3}{2 ^{\frac{2}{3} + 6} v ^{2}}

2^{6 + \frac{2}{3}} = 2^{6} \cdot 2^{\frac{2}{3}}

2^{6 + \frac{2}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{6} \cdot 2^{\frac{2}{3}}

= \frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Find Least Common Multiplier of

2^{6 + \frac{2}{3}} v^{2}, 8 : 64 \cdot 2^{\frac{2}{3}} v^{2}

2^{6 + \frac{2}{3}} v^{2}, 8

Lowest Common Multiplier (LCM)

Least Common Multiplier of

64, 8 : 64

64, 8

Least Common Multiplier (LCM)

Prime factorization of

64 : 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

64

64

divides by

264 = 32 \cdot 2

= 2 \cdot 32

32

divides by

232 = 16 \cdot 2

= 2 \cdot 2 \cdot 16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

Prime factorization of

8 : 2 \cdot 2 \cdot 2

8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2

Multiply each factor the greatest number of times it occurs in either

64

8

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

Multiply the numbers:

2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 = 64

= 64

Compute an expression comprised of factors that appear either in

64 \cdot 2^{\frac{2}{3}} v^{2}

8

= 64 \cdot 2^{\frac{2}{3}} v^{2}

Multiply by LCM=

64 \cdot 2^{\frac{2}{3}} v^{2}

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} - v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Simplify

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} - v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} = - \frac{2 ^{\frac{2}{3}}}{8} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Simplify

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} : 3

\frac{3}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 64 \cdot 2 ^{\frac{2}{3}} v ^{2}}{2 ^{6} \cdot 2 ^{\frac{2}{3}} v ^{2}}

Cancel the common factor:

2^{\frac{2}{3}}

= \frac{3 \cdot 64 v ^{2}}{2 ^{6} v ^{2}}

Cancel the common factor:

v^{2}

= \frac{3 \cdot 64}{2 ^{6}}

Multiply the numbers:

3 \cdot 64 = 192

= \frac{192}{2 ^{6}}

Factor

192 : 2^{6} \cdot 3

Factor

192 = 2^{6} \cdot 3

= \frac{2 ^{6} \cdot 3}{2 ^{6}}

Cancel the common factor:

2^{6}

= 3

Simplify

- v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} : - 64 \cdot 2^{\frac{2}{3}} v^{4}

- v^{2} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

v^{2} v^{2} = v^{2 + 2}

= - 64 \cdot 2^{\frac{2}{3}} v^{2 + 2}

Add the numbers:

2 + 2 = 4

= - 64 \cdot 2^{\frac{2}{3}} v^{4}

Simplify

- \frac{2 ^{\frac{2}{3}}}{8} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 ^{\frac{2}{3}} \cdot 64 \cdot 2 ^{\frac{2}{3}} v ^{2}}{8}

2^{\frac{2}{3}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2} = 64 \cdot 2^{2 \cdot \frac{2}{3}} v^{2}

2^{\frac{2}{3}} \cdot 64 \cdot 2^{\frac{2}{3}} v^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{2}{3}} \cdot 2^{\frac{2}{3}} = 2^{\frac{2}{3} + \frac{2}{3}}

= 64 \cdot 2^{\frac{2}{3} + \frac{2}{3}} v^{2}

Add similar elements:

\frac{2}{3} + \frac{2}{3} = 2 \cdot \frac{2}{3}

= 64 \cdot 2^{2 \cdot \frac{2}{3}} v^{2}

= - \frac{64 \cdot 2 ^{2 \cdot \frac{2}{3}} v ^{2}}{8}

Divide the numbers:

\frac{64}{8} = 8

= - 8 \cdot 2^{2 \cdot \frac{2}{3}} v^{2}

2^{2 \cdot \frac{2}{3}}

Multiply

2 \cdot \frac{2}{3} : \frac{4}{3}

2 \cdot \frac{2}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 2}{3}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{4}{3}

= 2^{\frac{4}{3}}

2^{\frac{4}{3}} = 2^{1 + \frac{1}{3}}

= 2^{1 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{1} \cdot 2^{\frac{1}{3}}

Refine

Multiply the numbers:

8 \cdot 2 = 16

Solve

Move

to the left side

Add

to both sides

Simplify

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

Find one solution for

- 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3 = 0

using Newton-Raphson:

v \approx 0.54556 \dots

- 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3 = 0

Newton-Raphson Approximation Definition

f (v) = - 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3

Find

f^{^{'}} (v) : - 406.37466 \dots v^{3} + 40.31747 \dots v

\frac{d}{d v} (- 101.59366 \dots v^{4} + 20.15873 \dots v^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d v} (101.59366 \dots v^{4}) + \frac{d}{d v} (20.15873 \dots v^{2}) + \frac{d}{d v} (3)

\frac{d}{d v} (101.59366 \dots v^{4}) = 406.37466 \dots v^{3}

\frac{d}{d v} (101.59366 \dots v^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 101.59366 \dots \frac{d}{d v} (v^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 101.59366 \dots \cdot 4 v^{4 - 1}

Simplify

= 406.37466 \dots v^{3}

\frac{d}{d v} (20.15873 \dots v^{2}) = 40.31747 \dots v

\frac{d}{d v} (20.15873 \dots v^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 20.15873 \dots \frac{d}{d v} (v^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 20.15873 \dots \cdot 2 v^{2 - 1}

Simplify

= 40.31747 \dots v

\frac{d}{d v} (3) = 0

\frac{d}{d v} (3)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

= - 406.37466 \dots v^{3} + 40.31747 \dots v + 0

Simplify

= - 406.37466 \dots v^{3} + 40.31747 \dots v

Let

v_{0} = 1

Compute

v_{n + 1}

until

Δ v_{n + 1} < 0.000001

v_{1} = 0.78573 \dots : Δ v_{1} = 0.21426 \dots

f (v_{0}) = - 101.59366 \dots \cdot 1^{4} + 20.15873 \dots \cdot 1^{2} + 3 = - 78.43493 \dots

f^{^{'}} (v_{0}) = - 406.37466 \dots \cdot 1^{3} + 40.31747 \dots \cdot 1 = - 366.05719 \dots

v_{1} = 0.78573 \dots

Δ v_{1} = ∣ 0.78573 \dots - 1 ∣ = 0.21426 \dots

Δ v_{1} = 0.21426 \dots

v_{2} = 0.64504 \dots : Δ v_{2} = 0.14068 \dots

f (v_{1}) = - 101.59366 \dots \cdot 0.78573 \dots^{4} + 20.15873 \dots \cdot 0.78573 \dots^{2} + 3 = - 23.27682 \dots

f^{^{'}} (v_{1}) = - 406.37466 \dots \cdot 0.78573 \dots^{3} + 40.31747 \dots \cdot 0.78573 \dots = - 165.44887 \dots

v_{2} = 0.64504 \dots

Δ v_{2} = ∣ 0.64504 \dots - 0.78573 \dots ∣ = 0.14068 \dots

Δ v_{2} = 0.14068 \dots

v_{3} = 0.57039 \dots : Δ v_{3} = 0.07465 \dots

f (v_{2}) = - 101.59366 \dots \cdot 0.64504 \dots^{4} + 20.15873 \dots \cdot 0.64504 \dots^{2} + 3 = - 6.20040 \dots

f^{^{'}} (v_{2}) = - 406.37466 \dots \cdot 0.64504 \dots^{3} + 40.31747 \dots \cdot 0.64504 \dots = - 83.05958 \dots

v_{3} = 0.57039 \dots

Δ v_{3} = ∣ 0.57039 \dots - 0.64504 \dots ∣ = 0.07465 \dots

Δ v_{3} = 0.07465 \dots

v_{4} = 0.54759 \dots : Δ v_{4} = 0.02280 \dots

f (v_{3}) = - 101.59366 \dots \cdot 0.57039 \dots^{4} + 20.15873 \dots \cdot 0.57039 \dots^{2} + 3 = - 1.19513 \dots

f^{^{'}} (v_{3}) = - 406.37466 \dots \cdot 0.57039 \dots^{3} + 40.31747 \dots \cdot 0.57039 \dots = - 52.41610 \dots

v_{4} = 0.54759 \dots

Δ v_{4} = ∣ 0.54759 \dots - 0.57039 \dots ∣ = 0.02280 \dots

Δ v_{4} = 0.02280 \dots

v_{5} = 0.54557 \dots : Δ v_{5} = 0.00201 \dots

f (v_{4}) = - 101.59366 \dots \cdot 0.54759 \dots^{4} + 20.15873 \dots \cdot 0.54759 \dots^{2} + 3 = - 0.08990 \dots

f^{^{'}} (v_{4}) = - 406.37466 \dots \cdot 0.54759 \dots^{3} + 40.31747 \dots \cdot 0.54759 \dots = - 44.64836 \dots

v_{5} = 0.54557 \dots

Δ v_{5} = ∣ 0.54557 \dots - 0.54759 \dots ∣ = 0.00201 \dots

Δ v_{5} = 0.00201 \dots

v_{6} = 0.54556 \dots : Δ v_{6} = 0.00001 \dots

f (v_{5}) = - 101.59366 \dots \cdot 0.54557 \dots^{4} + 20.15873 \dots \cdot 0.54557 \dots^{2} + 3 = - 0.00065 \dots

f^{^{'}} (v_{5}) = - 406.37466 \dots \cdot 0.54557 \dots^{3} + 40.31747 \dots \cdot 0.54557 \dots = - 43.99616 \dots

v_{6} = 0.54556 \dots

Δ v_{6} = ∣ 0.54556 \dots - 0.54557 \dots ∣ = 0.00001 \dots

Δ v_{6} = 0.00001 \dots

v_{7} = 0.54556 \dots : Δ v_{7} = 8.18838 E - 10

f (v_{6}) = - 101.59366 \dots \cdot 0.54556 \dots^{4} + 20.15873 \dots \cdot 0.54556 \dots^{2} + 3 = - 3.60218 E - 8

f^{^{'}} (v_{6}) = - 406.37466 \dots \cdot 0.54556 \dots^{3} + 40.31747 \dots \cdot 0.54556 \dots = - 43.99134 \dots

v_{7} = 0.54556 \dots

Δ v_{7} = ∣ 0.54556 \dots - 0.54556 \dots ∣ = 8.18838 E - 10

Δ v_{7} = 8.18838 E - 10

v \approx 0.54556 \dots

Apply long division:

- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots \approx 0

Find one solution for

- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots = 0

using Newton-Raphson:

v \approx - 0.54556 \dots

- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots = 0

Newton-Raphson Approximation Definition

f (v) = - 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots

Find

f^{^{'}} (v) : - 304.78100 \dots v^{2} - 110.85125 \dots v - 10.07936 \dots

\frac{d}{d v} (- 101.59366 \dots v^{3} - 55.42562 \dots v^{2} - 10.07936 \dots v - 5.49891 \dots)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d v} (101.59366 \dots v^{3}) - \frac{d}{d v} (55.42562 \dots v^{2}) - \frac{d}{d v} (10.07936 \dots v) - \frac{d}{d v} (5.49891 \dots)

\frac{d}{d v} (101.59366 \dots v^{3}) = 304.78100 \dots v^{2}

\frac{d}{d v} (101.59366 \dots v^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 101.59366 \dots \frac{d}{d v} (v^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 101.59366 \dots \cdot 3 v^{3 - 1}

Simplify

= 304.78100 \dots v^{2}

\frac{d}{d v} (55.42562 \dots v^{2}) = 110.85125 \dots v

\frac{d}{d v} (55.42562 \dots v^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 55.42562 \dots \frac{d}{d v} (v^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 55.42562 \dots \cdot 2 v^{2 - 1}

Simplify

= 110.85125 \dots v

\frac{d}{d v} (10.07936 \dots v) = 10.07936 \dots

\frac{d}{d v} (10.07936 \dots v)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10.07936 \dots \frac{d v}{d v}

Apply the common derivative:

\frac{d v}{d v} = 1

= 10.07936 \dots \cdot 1

Simplify

= 10.07936 \dots

\frac{d}{d v} (5.49891 \dots) = 0

\frac{d}{d v} (5.49891 \dots)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

= - 304.78100 \dots v^{2} - 110.85125 \dots v - 10.07936 \dots - 0

Simplify

= - 304.78100 \dots v^{2} - 110.85125 \dots v - 10.07936 \dots

Let

v_{0} = - 1

Compute

v_{n + 1}

until

Δ v_{n + 1} < 0.000001

v_{1} = - 0.75124 \dots : Δ v_{1} = 0.24875 \dots

f (v_{0}) = - 101.59366 \dots (- 1)^{3} - 55.42562 \dots (- 1)^{2} - 10.07936 \dots (- 1) - 5.49891 \dots = 50.74849 \dots

f^{^{'}} (v_{0}) = - 304.78100 \dots (- 1)^{2} - 110.85125 \dots (- 1) - 10.07936 \dots = - 204.00911 \dots

v_{1} = - 0.75124 \dots

Δ v_{1} = ∣ - 0.75124 \dots - (- 1) ∣ = 0.24875 \dots

Δ v_{1} = 0.24875 \dots

v_{2} = - 0.61091 \dots : Δ v_{2} = 0.14032 \dots

f (v_{1}) = - 101.59366 \dots (- 0.75124 \dots)^{3} - 55.42562 \dots (- 0.75124 \dots)^{2} - 10.07936 \dots (- 0.75124 \dots) - 5.49891 \dots = 13.86617 \dots

f^{^{'}} (v_{1}) = - 304.78100 \dots (- 0.75124 \dots)^{2} - 110.85125 \dots (- 0.75124 \dots) - 10.07936 \dots = - 98.81153 \dots

v_{2} = - 0.61091 \dots

Δ v_{2} = ∣ - 0.61091 \dots - (- 0.75124 \dots) ∣ = 0.14032 \dots

Δ v_{2} = 0.14032 \dots

v_{3} = - 0.55501 \dots : Δ v_{3} = 0.05590 \dots

f (v_{2}) = - 101.59366 \dots (- 0.61091 \dots)^{3} - 55.42562 \dots (- 0.61091 \dots)^{2} - 10.07936 \dots (- 0.61091 \dots) - 5.49891 \dots = 3.13665 \dots

f^{^{'}} (v_{2}) = - 304.78100 \dots (- 0.61091 \dots)^{2} - 110.85125 \dots (- 0.61091 \dots) - 10.07936 \dots = - 56.10803 \dots

v_{3} = - 0.55501 \dots

Δ v_{3} = ∣ - 0.55501 \dots - (- 0.61091 \dots) ∣ = 0.05590 \dots

Δ v_{3} = 0.05590 \dots

v_{4} = - 0.54579 \dots : Δ v_{4} = 0.00921 \dots

f (v_{3}) = - 101.59366 \dots (- 0.55501 \dots)^{3} - 55.42562 \dots (- 0.55501 \dots)^{2} - 10.07936 \dots (- 0.55501 \dots) - 5.49891 \dots = 0.39093 \dots

f^{^{'}} (v_{3}) = - 304.78100 \dots (- 0.55501 \dots)^{2} - 110.85125 \dots (- 0.55501 \dots) - 10.07936 \dots = - 42.43951 \dots

v_{4} = - 0.54579 \dots

Δ v_{4} = ∣ - 0.54579 \dots - (- 0.55501 \dots) ∣ = 0.00921 \dots

Δ v_{4} = 0.00921 \dots

v_{5} = - 0.54556 \dots : Δ v_{5} = 0.00023 \dots

f (v_{4}) = - 101.59366 \dots (- 0.54579 \dots)^{3} - 55.42562 \dots (- 0.54579 \dots)^{2} - 10.07936 \dots (- 0.54579 \dots) - 5.49891 \dots = 0.00957 \dots

f^{^{'}} (v_{4}) = - 304.78100 \dots (- 0.54579 \dots)^{2} - 110.85125 \dots (- 0.54579 \dots) - 10.07936 \dots = - 40.37008 \dots

v_{5} = - 0.54556 \dots

Δ v_{5} = ∣ - 0.54556 \dots - (- 0.54579 \dots) ∣ = 0.00023 \dots

Δ v_{5} = 0.00023 \dots

v_{6} = - 0.54556 \dots : Δ v_{6} = 1.54611 E - 7

f (v_{5}) = - 101.59366 \dots (- 0.54556 \dots)^{3} - 55.42562 \dots (- 0.54556 \dots)^{2} - 10.07936 \dots (- 0.54556 \dots) - 5.49891 \dots = 6.23352 E - 6

f^{^{'}} (v_{5}) = - 304.78100 \dots (- 0.54556 \dots)^{2} - 110.85125 \dots (- 0.54556 \dots) - 10.07936 \dots = - 40.31750 \dots

v_{6} = - 0.54556 \dots

Δ v_{6} = ∣ - 0.54556 \dots - (- 0.54556 \dots) ∣ = 1.54611 E - 7

Δ v_{6} = 1.54611 E - 7

v \approx - 0.54556 \dots

Apply long division:

\frac{- 101.59366 \dots v ^{3} - 55.42562 \dots v ^{2} - 10.07936 \dots v - 5.49891 \dots}{v + 0.54556 \dots} = - 101.59366 \dots v^{2} - 10.07936 \dots

- 101.59366 \dots v^{2} - 10.07936 \dots \approx 0

Find one solution for

- 101.59366 \dots v^{2} - 10.07936 \dots = 0

using Newton-Raphson:

No Solution for

v \in R

- 101.59366 \dots v^{2} - 10.07936 \dots = 0

Newton-Raphson Approximation Definition

f (v) = - 101.59366 \dots v^{2} - 10.07936 \dots

Find

f^{^{'}} (v) : - 203.18733 \dots v

\frac{d}{d v} (- 101.59366 \dots v^{2} - 10.07936 \dots)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d v} (101.59366 \dots v^{2}) - \frac{d}{d v} (10.07936 \dots)

\frac{d}{d v} (101.59366 \dots v^{2}) = 203.18733 \dots v

\frac{d}{d v} (101.59366 \dots v^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 101.59366 \dots \frac{d}{d v} (v^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 101.59366 \dots \cdot 2 v^{2 - 1}

Simplify

= 203.18733 \dots v

\frac{d}{d v} (10.07936 \dots) = 0

\frac{d}{d v} (10.07936 \dots)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

= - 203.18733 \dots v - 0

Simplify

= - 203.18733 \dots v

Let

v_{0} = - 1

Compute

v_{n + 1}

until

Δ v_{n + 1} < 0.000001

v_{1} = - 0.45039 \dots : Δ v_{1} = 0.54960 \dots

f (v_{0}) = - 101.59366 \dots (- 1)^{2} - 10.07936 \dots = - 111.67303 \dots

f^{^{'}} (v_{0}) = - 203.18733 \dots (- 1) = 203.18733 \dots

v_{1} = - 0.45039 \dots

Δ v_{1} = ∣ - 0.45039 \dots - (- 1) ∣ = 0.54960 \dots

Δ v_{1} = 0.54960 \dots

v_{2} = - 0.11505 \dots : Δ v_{2} = 0.33533 \dots

f (v_{1}) = - 101.59366 \dots (- 0.45039 \dots)^{2} - 10.07936 \dots = - 30.68810 \dots

f^{^{'}} (v_{1}) = - 203.18733 \dots (- 0.45039 \dots) = 91.51429 \dots

v_{2} = - 0.11505 \dots

Δ v_{2} = ∣ - 0.11505 \dots - (- 0.45039 \dots) ∣ = 0.33533 \dots

Δ v_{2} = 0.33533 \dots

v_{3} = 0.37361 \dots : Δ v_{3} = 0.48867 \dots

f (v_{2}) = - 101.59366 \dots (- 0.11505 \dots)^{2} - 10.07936 \dots = - 11.42427 \dots

f^{^{'}} (v_{2}) = - 203.18733 \dots (- 0.11505 \dots) = 23.37813 \dots

v_{3} = 0.37361 \dots

Δ v_{3} = ∣ 0.37361 \dots - (- 0.11505 \dots) ∣ = 0.48867 \dots

Δ v_{3} = 0.48867 \dots

v_{4} = 0.05403 \dots : Δ v_{4} = 0.31958 \dots

f (v_{3}) = - 101.59366 \dots \cdot 0.37361 \dots^{2} - 10.07936 \dots = - 24.26076 \dots

f^{^{'}} (v_{3}) = - 203.18733 \dots \cdot 0.37361 \dots = - 75.91416 \dots

v_{4} = 0.05403 \dots

Δ v_{4} = ∣ 0.05403 \dots - 0.37361 \dots ∣ = 0.31958 \dots

Δ v_{4} = 0.31958 \dots

v_{5} = - 0.89102 \dots : Δ v_{5} = 0.94505 \dots

f (v_{4}) = - 101.59366 \dots \cdot 0.05403 \dots^{2} - 10.07936 \dots = - 10.37600 \dots

f^{^{'}} (v_{4}) = - 203.18733 \dots \cdot 0.05403 \dots = - 10.97924 \dots

v_{5} = - 0.89102 \dots

Δ v_{5} = ∣ - 0.89102 \dots - 0.05403 \dots ∣ = 0.94505 \dots

Δ v_{5} = 0.94505 \dots

v_{6} = - 0.38983 \dots : Δ v_{6} = 0.50118 \dots

f (v_{5}) = - 101.59366 \dots (- 0.89102 \dots)^{2} - 10.07936 \dots = - 90.73642 \dots

f^{^{'}} (v_{5}) = - 203.18733 \dots (- 0.89102 \dots) = 181.04414 \dots

v_{6} = - 0.38983 \dots

Δ v_{6} = ∣ - 0.38983 \dots - (- 0.89102 \dots) ∣ = 0.50118 \dots

Δ v_{6} = 0.50118 \dots

v_{7} = - 0.06766 \dots : Δ v_{7} = 0.32216 \dots

f (v_{6}) = - 101.59366 \dots (- 0.38983 \dots)^{2} - 10.07936 \dots = - 25.51884 \dots

f^{^{'}} (v_{6}) = - 203.18733 \dots (- 0.38983 \dots) = 79.20991 \dots

v_{7} = - 0.06766 \dots

Δ v_{7} = ∣ - 0.06766 \dots - (- 0.38983 \dots) ∣ = 0.32216 \dots

Δ v_{7} = 0.32216 \dots

v_{8} = 0.69923 \dots : Δ v_{8} = 0.76690 \dots

f (v_{7}) = - 101.59366 \dots (- 0.06766 \dots)^{2} - 10.07936 \dots = - 10.54458 \dots

f^{^{'}} (v_{7}) = - 203.18733 \dots (- 0.06766 \dots) = 13.74960 \dots

v_{8} = 0.69923 \dots

Δ v_{8} = ∣ 0.69923 \dots - (- 0.06766 \dots) ∣ = 0.76690 \dots

Δ v_{8} = 0.76690 \dots

v_{9} = 0.27867 \dots : Δ v_{9} = 0.42055 \dots

f (v_{8}) = - 101.59366 \dots \cdot 0.69923 \dots^{2} - 10.07936 \dots = - 59.75094 \dots

f^{^{'}} (v_{8}) = - 203.18733 \dots \cdot 0.69923 \dots = - 142.07487 \dots

v_{9} = 0.27867 \dots

Δ v_{9} = ∣ 0.27867 \dots - 0.69923 \dots ∣ = 0.42055 \dots

Δ v_{9} = 0.42055 \dots

v_{10} = - 0.03867 \dots : Δ v_{10} = 0.31734 \dots

f (v_{9}) = - 101.59366 \dots \cdot 0.27867 \dots^{2} - 10.07936 \dots = - 17.96890 \dots

f^{^{'}} (v_{9}) = - 203.18733 \dots \cdot 0.27867 \dots = - 56.62250 \dots

v_{10} = - 0.03867 \dots

Δ v_{10} = ∣ - 0.03867 \dots - 0.27867 \dots ∣ = 0.31734 \dots

Δ v_{10} = 0.31734 \dots

v_{11} = 1.26333 \dots : Δ v_{11} = 1.30200 \dots

f (v_{10}) = - 101.59366 \dots (- 0.03867 \dots)^{2} - 10.07936 \dots = - 10.23132 \dots

f^{^{'}} (v_{10}) = - 203.18733 \dots (- 0.03867 \dots) = 7.85811 \dots

v_{11} = 1.26333 \dots

Δ v_{11} = ∣ 1.26333 \dots - (- 0.03867 \dots) ∣ = 1.30200 \dots

Δ v_{11} = 1.30200 \dots

Cannot find solution

The solutions are

v \approx 0.54556 \dots, v \approx - 0.54556 \dots

v \approx 0.54556 \dots, v \approx - 0.54556 \dots

Verify Solutions

Find undefined (singularity) points:

v = 0

Take the denominator(s) of

(- \frac{3}{2 ^{\frac{10}{3}} v})^{2} - v^{2}

and compare to zero

Solve

2^{\frac{10}{3}} v = 0 : v = 0

2^{\frac{10}{3}} v = 0

Divide both sides by

2^{\frac{10}{3}}

2^{\frac{10}{3}} v = 0

Divide both sides by

2^{\frac{10}{3}}

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}} = \frac{0}{2 ^{\frac{10}{3}}}

Simplify

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}} = \frac{0}{2 ^{\frac{10}{3}}}

Simplify

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}} : v

\frac{2 ^{\frac{10}{3}} v}{2 ^{\frac{10}{3}}}

Cancel the common factor:

2^{\frac{10}{3}}

= v

Simplify

\frac{0}{2 ^{\frac{10}{3}}} : 0

\frac{0}{2 ^{\frac{10}{3}}}

Apply rule

\frac{0}{a} = 0

a \neq = 0

= 0

v = 0

v = 0

v = 0

The following points are undefined

v = 0

Combine undefined points with solutions:

v \approx 0.54556 \dots, v \approx - 0.54556 \dots

Plug the solutions

v = 0.54556 \dots, v = - 0.54556 \dots

into

2 uv = - \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

For

2 uv = - \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

For

2 uv = - \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

0.54556 \dots

2 u \cdot 0.54556 \dots = - \frac{2 ^{\frac{2}{3}} 3}{8}

Solve

2 u \cdot 0.54556 \dots = - \frac{2 ^{\frac{2}{3}} 3}{8}

Simplify

- \frac{2 ^{\frac{2}{3}} 3}{8} : - \frac{3}{2 ^{\frac{7}{3}}}

- \frac{2 ^{\frac{2}{3}} 3}{8}

Factor the number:

8 = 2^{3}

= - \frac{2 ^{\frac{2}{3}} 3}{2 ^{3}}

Simplify

\frac{2 ^{\frac{2}{3}}}{2 ^{3}} : \frac{1}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

= \frac{1}{2 ^{3 - \frac{2}{3}}}

3 - \frac{2}{3} = \frac{7}{3}

3 - \frac{2}{3}

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= \frac{3 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 3 - 2}{3}

3 \cdot 3 - 2 = 7

3 \cdot 3 - 2

Multiply the numbers:

3 \cdot 3 = 9

= 9 - 2

Subtract the numbers:

9 - 2 = 7

= 7

= \frac{7}{3}

= \frac{1}{2 ^{\frac{7}{3}}}

= - \frac{3}{2 ^{\frac{7}{3}}}

2 u \cdot 0.54556 \dots = - \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 \cdot 0.54556 \dots

2 u \cdot 0.54556 \dots = - \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 \cdot 0.54556 \dots

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots} = \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 \cdot 0.54556 \dots}

Simplify

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots} = \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 \cdot 0.54556 \dots}

Simplify

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots} : u

\frac{2 u \cdot 0.54556 \dots}{2 \cdot 0.54556 \dots}

Cancel the common factor:

2

= \frac{u \cdot 0.54556 \dots}{0.54556 \dots}

Cancel the common factor:

0.54556 \dots

= u

Simplify

\frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 \cdot 0.54556 \dots}

Multiply the numbers:

2 \cdot 0.54556 \dots = 1.09112 \dots

= \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{1.09112 \dots}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{2 ^{\frac{7}{3}}}}{1.09112 \dots}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2 ^{\frac{7}{3}}}}{1.09112 \dots} = \frac{3}{2 ^{\frac{7}{3}} \cdot 1.09112 \dots}

= - \frac{3}{2 ^{\frac{7}{3}} \cdot 1.09112 \dots}

2^{\frac{7}{3}}

2^{\frac{7}{3}} = 2^{2 + \frac{1}{3}}

= 2^{2 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{2} \cdot 2^{\frac{1}{3}}

Refine

For

2 uv = - \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

For

2 uv = - \frac{2 ^{\frac{2}{3}} \cdot 3}{8}

, subsitute

v

with

- 0.54556 \dots

2 u (- 0.54556 \dots) = - \frac{2 ^{\frac{2}{3}} 3}{8}

Solve

2 u (- 0.54556 \dots) = - \frac{2 ^{\frac{2}{3}} 3}{8}

Simplify

- \frac{2 ^{\frac{2}{3}} 3}{8} : - \frac{3}{2 ^{\frac{7}{3}}}

- \frac{2 ^{\frac{2}{3}} 3}{8}

Factor the number:

8 = 2^{3}

= - \frac{2 ^{\frac{2}{3}} 3}{2 ^{3}}

Simplify

\frac{2 ^{\frac{2}{3}}}{2 ^{3}} : \frac{1}{2 ^{\frac{7}{3}}}

\frac{2 ^{\frac{2}{3}}}{2 ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

= \frac{1}{2 ^{3 - \frac{2}{3}}}

3 - \frac{2}{3} = \frac{7}{3}

3 - \frac{2}{3}

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= \frac{3 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 3 - 2}{3}

3 \cdot 3 - 2 = 7

3 \cdot 3 - 2

Multiply the numbers:

3 \cdot 3 = 9

= 9 - 2

Subtract the numbers:

9 - 2 = 7

= 7

= \frac{7}{3}

= \frac{1}{2 ^{\frac{7}{3}}}

= - \frac{3}{2 ^{\frac{7}{3}}}

2 u (- 0.54556 \dots) = - \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 (- 0.54556 \dots)

2 u (- 0.54556 \dots) = - \frac{3}{2 ^{\frac{7}{3}}}

Divide both sides by

2 (- 0.54556 \dots)

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )} = \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 ( - 0.54556 \dots )}

Simplify

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )} = \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 ( - 0.54556 \dots )}

Simplify

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )} : u

\frac{2 u ( - 0.54556 \dots )}{2 ( - 0.54556 \dots )}

Multiply the numbers:

2 (- 0.54556 \dots) = - 1.09112 \dots

= \frac{- 1.09112 \dots u}{- 1.09112 \dots}

Cancel the common factor:

- 1.09112 \dots

= u

Simplify

\frac{- \frac{3}{2 ^{\frac{7}{3}}}}{2 ( - 0.54556 \dots )}

Remove parentheses:

(- a) = - a

= \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{- 2 \cdot 0.54556 \dots}

Multiply the numbers:

2 \cdot 0.54556 \dots = 1.09112 \dots

= \frac{- \frac{3}{2 ^{\frac{7}{3}}}}{- 1.09112 \dots}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{\frac{3}{2 ^{\frac{7}{3}}}}{1.09112 \dots}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 ^{\frac{7}{3}} \cdot 1.09112 \dots}

2^{\frac{7}{3}}

2^{\frac{7}{3}} = 2^{2 + \frac{1}{3}}

= 2^{2 + \frac{1}{3}}

Apply exponent rule:

x^{a + b} = x^{a} x^{b}

= 2^{2} \cdot 2^{\frac{1}{3}}

Refine

Verify solutions by plugging them into the original equations

Check the solutions by plugging them into

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Remove the ones that don't agree with the equation.

Check the solution

True

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Plug in

Refine

True

Check the solution

True

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}

Plug in

Refine

True

Check the solutions by plugging them into

2 uv = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Remove the ones that don't agree with the equation.

Check the solution

True

2 uv = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Plug in

Refine

- \frac{3 \cdot 2 ^{\frac{2}{3}} \cdot 0.54556 \dots}{4.36449 \dots} = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

True

Check the solution

True

2 uv = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

Plug in

Refine

- \frac{3 \cdot 2 ^{\frac{2}{3}} \cdot 0.54556 \dots}{4.36449 \dots} = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

True

Therefore, the final solutions for

u^{2} - v^{2} = - \frac{2 ^{\frac{2}{3}}}{8}, 2 uv = - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8}

are

Substitute back

w = u + v i

The solutions are

Substitute back

w = cos (x)

cos (x) = \frac{2 ^{\frac{2}{3}}}{2} : x = arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = 2 π - arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn

cos (x) = \frac{2 ^{\frac{2}{3}}}{2}

Apply trig inverse properties

cos (x) = \frac{2 ^{\frac{2}{3}}}{2}

General solutions for

cos (x) = \frac{2 ^{\frac{2}{3}}}{2}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = 2 π - arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn

x = arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = 2 π - arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn

cos (x) = - \frac{2 ^{\frac{2}{3}}}{2} : x = arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = - arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn

cos (x) = - \frac{2 ^{\frac{2}{3}}}{2}

Apply trig inverse properties

cos (x) = - \frac{2 ^{\frac{2}{3}}}{2}

General solutions for

cos (x) = - \frac{2 ^{\frac{2}{3}}}{2}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = - arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn

x = arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = - arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn

No Solution

Simplify

2^{2} = 4

Multiply the numbers:

4 \cdot 1.09112 \dots = 4.36449 \dots

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4.36449 \dots \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 2 \cdot 4.36449 \dots

Multiply the numbers:

4.36449 \dots \cdot 2 = 8.72898 \dots

= 8.72898 \dots

= \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots}

= \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots} + 0.54556 \dots i

No Solution

No Solution

Simplify

2^{2} = 4

Multiply the numbers:

4 \cdot 1.09112 \dots = 4.36449 \dots

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4.36449 \dots \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 2 \cdot 4.36449 \dots

Multiply the numbers:

4.36449 \dots \cdot 2 = 8.72898 \dots

= 8.72898 \dots

= \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots}

= - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots} - 0.54556 \dots i

No Solution

No Solution

Simplify

2^{2} = 4

Multiply the numbers:

4 \cdot 1.09112 \dots = 4.36449 \dots

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4.36449 \dots \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 2 \cdot 4.36449 \dots

Multiply the numbers:

4.36449 \dots \cdot 2 = 8.72898 \dots

= 8.72898 \dots

= \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots}

= - \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots} + 0.54556 \dots i

No Solution

No Solution

Simplify

2^{2} = 4

Multiply the numbers:

4 \cdot 1.09112 \dots = 4.36449 \dots

Multiply by the conjugate

\frac{2 ^{\frac{2}{3}}}{2 ^{\frac{2}{3}}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

= 4.36449 \dots \cdot 2^{\frac{2}{3} + \frac{1}{3}}

2^{\frac{2}{3} + \frac{1}{3}} = 2

2^{\frac{2}{3} + \frac{1}{3}}

Combine the fractions

\frac{2}{3} + \frac{1}{3} : 1

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= 2 \cdot 4.36449 \dots

Multiply the numbers:

4.36449 \dots \cdot 2 = 8.72898 \dots

= 8.72898 \dots

= \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots}

= \frac{3 \cdot 2 ^{\frac{2}{3}}}{8.72898 \dots} - 0.54556 \dots i

No Solution

Combine all the solutions

x = arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = 2 π - arccos (\frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn, x = - arccos (- \frac{2 ^{\frac{2}{3}}}{2}) + 2 πn

Show solutions in decimal form

x = 0.88929 \dots + 2 πn, x = 2 π - 0.88929 \dots + 2 πn, x = 2.25229 \dots + 2 πn, x = - 2.25229 \dots + 2 πn

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