What is the value of sin(arccos(-4/5)) ?

The value of sin(arccos(-4/5)) is 3/5

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sin(arccos(-4/5))

sin (arccos (- \frac{4}{5}))

\frac{3}{5}

Decimal Notation

0.6

Solution steps

sin (arccos (- \frac{4}{5}))

Rewrite using trig identities:

sin (arccos (- \frac{4}{5})) = 1 - (- \frac{4}{5})^{2}

Use the following identity:

sin (arccos (x)) = 1 - x^{2}

= 1 - (- \frac{4}{5})^{2}

= 1 - (- \frac{4}{5})^{2}

Simplify

= \frac{3}{5}

cos (arcsin (- \frac{2}{3}))

\frac{67}{tan ( 4 2 ^{\circ} )}

19 sin (2 8^{\circ})

cos (2) (150)

sin (arcsin (0.6))