What is the general solution for sin(a)=-(sqrt(3))/2 ?

The general solution for sin(a)=-(sqrt(3))/2 is a=(4pi)/3+2pin,a=(5pi)/3+2pin

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sin(a)=-(sqrt(3))/2

sin (a) = - \frac{3}{2}

a = \frac{4 π}{3} + 2 πn, a = \frac{5 π}{3} + 2 πn

Degrees

a = 24 0^{\circ} + 36 0^{\circ} n, a = 30 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (a) = - \frac{3}{2}

General solutions for

sin (a) = - \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

a = \frac{4 π}{3} + 2 πn, a = \frac{5 π}{3} + 2 πn

a = \frac{4 π}{3} + 2 πn, a = \frac{5 π}{3} + 2 πn

t, v = 311 cos (30 t + 3 0^{\circ}) v

cos^{2} (x) = 2 sin (x)

sin^{4} (θ) + cos^{4} (θ) = 2 sin^{2} (θ) - 1

x, \frac{- y}{2} + sin (x) = 0

cos (a) = 0.33

What is the general solution for sin(a)=-(sqrt(3))/2 ?
The general solution for sin(a)=-(sqrt(3))/2 is a=(4pi)/3+2pin,a=(5pi)/3+2pin