What is the general solution for 3-cos(x)=3-sin(x) ?

The general solution for 3-cos(x)=3-sin(x) is x= pi/4+pin

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3-cos(x)=3-sin(x)

3 - cos (x) = 3 - sin (x)

x = \frac{π}{4} + πn

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

3 - cos (x) = 3 - sin (x)

Subtract

3 - sin (x)

from both sides

sin (x) - cos (x) = 0

Rewrite using trig identities

sin (x) - cos (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{sin ( x ) - cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

\frac{sin ( x )}{cos ( x )} - 1 = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

tan (x) - 1 = 0

tan (x) - 1 = 0

Move

1

to the right side

tan (x) - 1 = 0

Add

1

to both sides

tan (x) - 1 + 1 = 0 + 1

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

cos (t) = \frac{1}{3}, 0 < t < \frac{1}{2} π

x, sin (x) - cos (x) = 1

x, sin (x) cos (y) = 1

sin (4 x) cos (7 x) - cos (4 x) sin (7 x) = - 0.6

cos (x) = \frac{40}{41}

What is the general solution for 3-cos(x)=3-sin(x) ?
The general solution for 3-cos(x)=3-sin(x) is x= pi/4+pin