What is the general solution for sin(x)=(sqrt(5))/5 ,sin(2x) ?

The general solution for sin(x)=(sqrt(5))/5 ,sin(2x) is No Solution for x\in\mathbb{R}

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sin(x)=(sqrt(5))/5 ,sin(2x)

sin (x) = \frac{5}{5}, sin (2 x)

No Solution for x \in R

Solution steps

sin (x) = \frac{5}{5}, sin (2 x)

Apply trig inverse properties

sin (x) = \frac{5}{5}

General solutions for

sin (x) = \frac{5}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{5}{5}) + 2 πn, x = π - arcsin (\frac{5}{5}) + 2 πn

x = arcsin (\frac{5}{5}) + 2 πn, x = π - arcsin (\frac{5}{5}) + 2 πn

Solutions for the range

sin (2 x)

No Solution for x \in R

0 = 1 - cos (2 π x)

tan (θ) = \frac{12}{5}, 0 \leq θ \leq \frac{π}{2}

sin (x) = \frac{420}{2.3}

cos (x) = \frac{14}{14}

x, 5 = 4 cos (3 x) + 9

What is the general solution for sin(x)=(sqrt(5))/5 ,sin(2x) ?
The general solution for sin(x)=(sqrt(5))/5 ,sin(2x) is No Solution for x\in\mathbb{R}