What is the general solution for arctan(θ)= 2/(2sqrt(3)) ?

The general solution for arctan(θ)= 2/(2sqrt(3)) is θ=tan((sqrt(3))/3)

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arctan(θ)= 2/(2sqrt(3))

arctan (θ) = \frac{2}{2 3}

θ = tan (\frac{3}{3})

Solution steps

arctan (θ) = \frac{2}{2 3}

Simplify

\frac{2}{2 3} : \frac{3}{3}

\frac{2}{2 3}

Divide the numbers:

\frac{2}{2} = 1

= \frac{1}{3}

Rationalize

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{3}

= \frac{3}{3}

arctan (θ) = \frac{3}{3}

Apply trig inverse properties

arctan (θ) = \frac{3}{3}

arctan (x) = a \Rightarrow x = tan (a)

θ = tan (\frac{3}{3})

θ = tan (\frac{3}{3})

3 sin (x) = + sin (x)

x, (D^{2} - 3 D + 2) y = sec^{2} (e^{- x})

sin (θ) = \frac{7 sin ( 14 0 ^{\circ} )}{16.12288984}

- 5 cos^{2} (x) = 0

tan (2 x) + sec (2 x) = 5

What is the general solution for arctan(θ)= 2/(2sqrt(3)) ?
The general solution for arctan(θ)= 2/(2sqrt(3)) is θ=tan((sqrt(3))/3)