What is the general solution for solvefor θ,2sin(θ)-5=0 ?

The general solution for solvefor θ,2sin(θ)-5=0 is No Solution for θ\in\mathbb{R}

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solvefor θ,2sin(θ)-5=0

solve for

θ, 2 sin (θ) - 5 = 0

No Solution for θ \in R

Solution steps

2 sin (θ) - 5 = 0

Move

5

to the right side

2 sin (θ) - 5 = 0

Add

5

to both sides

2 sin (θ) - 5 + 5 = 0 + 5

Simplify

2 sin (θ) = 5

2 sin (θ) = 5

Divide both sides by

2

2 sin (θ) = 5

Divide both sides by

2

\frac{2 sin ( θ )}{2} = \frac{5}{2}

Simplify

sin (θ) = \frac{5}{2}

sin (θ) = \frac{5}{2}

- 1 \leq sin (x) \leq 1

No Solution for θ \in R

(tan (x) - 3) (2 sin (x) - 1) = 0

- 2 (sin^{2} (x) - cos^{2} (x)) = 0

2 sin^{2} (x) - 5 sin (x) - 4 = 0

sin (θ) = 0.4815

6 cos^{2} (2 x) = sin (2 x) + 5

What is the general solution for solvefor θ,2sin(θ)-5=0 ?
The general solution for solvefor θ,2sin(θ)-5=0 is No Solution for θ\in\mathbb{R}