What is the general solution for tan(θ)=(-sqrt(3)) ?

The general solution for tan(θ)=(-sqrt(3)) is θ=(2pi)/3+pin

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tan(θ)=(-sqrt(3))

tan (θ) = (- 3)

θ = \frac{2 π}{3} + πn

Degrees

θ = 12 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = (- 3)

General solutions for

tan (θ) = - 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{2 π}{3} + πn

θ = \frac{2 π}{3} + πn

sin^{2} (x) + cos (x) + 1 = 0, 0 \leq x \leq 2 π

sin (2 x) = \frac{- 1}{3}

cos (2 θ) = 1 + 3 sin (θ)

cos (2 x) - cos (x) = - 1, 0 \leq x < 2 π

sin (x) = - \frac{1}{10}

What is the general solution for tan(θ)=(-sqrt(3)) ?
The general solution for tan(θ)=(-sqrt(3)) is θ=(2pi)/3+pin