What is the general solution for -cos(x)=-1 ?

The general solution for -cos(x)=-1 is x=2pin

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-cos(x)=-1

- cos (x) = - 1

x = 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n

Solution steps

- cos (x) = - 1

Divide both sides by

- 1

- cos (x) = - 1

Divide both sides by

- 1

\frac{- cos ( x )}{- 1} = \frac{- 1}{- 1}

Simplify

cos (x) = 1

cos (x) = 1

General solutions for

cos (x) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

sin^{2} (x) csc (x) = - \frac{1}{2}

sec^{2} (2 x) - 1 = 0

1 = 2 cos (x)

x, y = arcsin (\frac{x}{11})

\frac{sin ( 4 8 ^{\circ} )}{13} = \frac{sin ( b )}{16}

What is the general solution for -cos(x)=-1 ?
The general solution for -cos(x)=-1 is x=2pin