What is the general solution for sin(3m)=0 ?

The general solution for sin(3m)=0 is m=(2pin)/3 ,m= pi/3+(2pin)/3

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sin(3m)=0

sin (3 m) = 0

m = \frac{2 πn}{3}, m = \frac{π}{3} + \frac{2 πn}{3}

Degrees

m = 0^{\circ} + 12 0^{\circ} n, m = 6 0^{\circ} + 12 0^{\circ} n

Solution steps

sin (3 m) = 0

General solutions for

sin (3 m) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

3 m = 0 + 2 πn, 3 m = π + 2 πn

3 m = 0 + 2 πn, 3 m = π + 2 πn

Solve

3 m = 0 + 2 πn : m = \frac{2 πn}{3}

3 m = 0 + 2 πn

0 + 2 πn = 2 πn

3 m = 2 πn

Divide both sides by

3

3 m = 2 πn

Divide both sides by

3

\frac{3 m}{3} = \frac{2 πn}{3}

Simplify

m = \frac{2 πn}{3}

m = \frac{2 πn}{3}

Solve

3 m = π + 2 πn : m = \frac{π}{3} + \frac{2 πn}{3}

3 m = π + 2 πn

Divide both sides by

3

3 m = π + 2 πn

Divide both sides by

3

\frac{3 m}{3} = \frac{π}{3} + \frac{2 πn}{3}

Simplify

m = \frac{π}{3} + \frac{2 πn}{3}

m = \frac{π}{3} + \frac{2 πn}{3}

m = \frac{2 πn}{3}, m = \frac{π}{3} + \frac{2 πn}{3}

cos (a) = - \frac{8}{17}, sin (b) = \frac{3}{5}

7 tan (θ) + 9 = 0

14 = - 3.75 cos (\frac{π}{6} x) + 11.25

x, f = sin (π \cdot ⌊ x ⌋)

(sin (x)) (tan (x) + 1) (cos (x) + 1) = 0

What is the general solution for sin(3m)=0 ?
The general solution for sin(3m)=0 is m=(2pin)/3 ,m= pi/3+(2pin)/3