What is the general solution for tan(φ)=-1/(sqrt(3)) ?

The general solution for tan(φ)=-1/(sqrt(3)) is φ=(5pi)/6+pin

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tan(φ)=-1/(sqrt(3))

tan (φ) = - \frac{1}{3}

φ = \frac{5 π}{6} + πn

Solution steps

tan (φ) = - \frac{1}{3}

Simplify

- \frac{1}{3} : - \frac{3}{3}

- \frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= - \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= - \frac{3}{3}

tan (φ) = - \frac{3}{3}

General solutions for

tan (φ) = - \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

φ = \frac{5 π}{6} + πn

φ = \frac{5 π}{6} + πn

sin (3 m) = 0

cos (a) = - \frac{8}{17}, sin (b) = \frac{3}{5}

7 tan (θ) + 9 = 0

14 = - 3.75 cos (\frac{π}{6} x) + 11.25

x, f = sin (π \cdot ⌊ x ⌋)

What is the general solution for tan(φ)=-1/(sqrt(3)) ?
The general solution for tan(φ)=-1/(sqrt(3)) is φ=(5pi)/6+pin