What is the general solution for cos(x)=(5sqrt(2))/(10) ?

The general solution for cos(x)=(5sqrt(2))/(10) is x= pi/4+2pin,x=(7pi)/4+2pin

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cos(x)=(5sqrt(2))/(10)

cos (x) = \frac{5 2}{10}

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Degrees

x = 4 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = \frac{5 2}{10}

Cancel the common factor:

5

cos (x) = \frac{2}{2}

General solutions for

cos (x) = \frac{2}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

4 tan (x) + 4 = 0

4 sin (θ) - 3 = 0, 0 \leq θ \leq 2 π

x, 0 = - 5 sin (2 x)

1.2 sin (2 4^{\circ}) = 1.2 sin (x)

cos (C) = 20.09 - \frac{27.1441}{19.6}

What is the general solution for cos(x)=(5sqrt(2))/(10) ?
The general solution for cos(x)=(5sqrt(2))/(10) is x= pi/4+2pin,x=(7pi)/4+2pin