What is the general solution for (cos(t))/(3cos(3t))=0 ?

The general solution for (cos(t))/(3cos(3t))=0 is No Solution for t\in\mathbb{R}

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(cos(t))/(3cos(3t))=0

\frac{cos ( t )}{3 cos ( 3 t )} = 0

No Solution for t \in R

Solution steps

\frac{cos ( t )}{3 cos ( 3 t )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn, \frac{3 π}{2} + 2 πn

No Solution for t \in R

3 tan (3 x) = 1

x, cos (x) + 3 = - cos (x)

2 cos (2 x) + 1 = 0

3 tan (x - 1) = 4, x \leq 2 π, 0

sin (x) = \frac{6 sin ( 2 0 ^{\circ} )}{4}

What is the general solution for (cos(t))/(3cos(3t))=0 ?
The general solution for (cos(t))/(3cos(3t))=0 is No Solution for t\in\mathbb{R}