What is the general solution for sin(θ)=0.7cos(90-θ) ?

The general solution for sin(θ)=0.7cos(90-θ) is θ=360n,θ=180+360n

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Popular >

sin(θ)=0.7cos(90-θ)

Solution

sin (θ) = 0.7 cos (9 0^{\circ} - θ)

Solution

θ = 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

Radians

θ = 0 + 2 πn, θ = π + 2 πn

Solution steps

sin (θ) = 0.7 cos (9 0^{\circ} - θ)

Rewrite using trig identities

sin (θ) = 0.7 cos (9 0^{\circ} - θ)

Rewrite using trig identities

cos (9 0^{\circ} - θ)

Use the Angle Difference identity:

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

= cos (9 0^{\circ}) cos (θ) + sin (9 0^{\circ}) sin (θ)

Simplify

cos (9 0^{\circ}) cos (θ) + sin (9 0^{\circ}) sin (θ) : sin (θ)

cos (9 0^{\circ}) cos (θ) + sin (9 0^{\circ}) sin (θ)

cos (9 0^{\circ}) cos (θ) = 0

cos (9 0^{\circ}) cos (θ)

Simplify

cos (9 0^{\circ}) : 0

cos (9 0^{\circ})

Use the following trivial identity:

cos (9 0^{\circ}) = 0

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

= 0 \cdot cos (θ)

Apply rule

0 \cdot a = 0

= 0

sin (9 0^{\circ}) sin (θ) = sin (θ)

sin (9 0^{\circ}) sin (θ)

Simplify

sin (9 0^{\circ}) : 1

sin (9 0^{\circ})

Use the following trivial identity:

sin (9 0^{\circ}) = 1

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1 \cdot sin (θ)

Multiply:

1 \cdot sin (θ) = sin (θ)

= sin (θ)

= 0 + sin (θ)

0 + sin (θ) = sin (θ)

= sin (θ)

= sin (θ)

sin (θ) = 0.7 sin (θ)

sin (θ) = 0.7 sin (θ)

Subtract

0.7 sin (θ)

from both sides

0.3 sin (θ) = 0

Multiply both sides by

10

0.3 sin (θ) = 0

To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere is one digit to the right of the decimal point, therefore multiply by

10

0.3 sin (θ) \cdot 10 = 0 \cdot 10

Refine

3 sin (θ) = 0

3 sin (θ) = 0

Divide both sides by

3

3 sin (θ) = 0

Divide both sides by

3

\frac{3 sin ( θ )}{3} = \frac{0}{3}

Simplify

sin (θ) = 0

sin (θ) = 0

General solutions for

sin (θ) = 0

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = 0 + 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

θ = 0 + 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

Solve

θ = 0 + 36 0^{\circ} n : θ = 36 0^{\circ} n

θ = 0 + 36 0^{\circ} n

0 + 36 0^{\circ} n = 36 0^{\circ} n

θ = 36 0^{\circ} n

θ = 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

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Frequently Asked Questions (FAQ)

What is the general solution for sin(θ)=0.7cos(90-θ) ?
The general solution for sin(θ)=0.7cos(90-θ) is θ=360n,θ=180+360n