What is the general solution for cos(θ)=(4k-1)/3 ?

The general solution for cos(θ)=(4k-1)/3 is θ=arccos((4k-1)/3)+2pin,θ=-arccos((4k-1)/3)+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)=(4k-1)/3

cos (θ) = \frac{4 k - 1}{3}

θ = arccos (\frac{4 k - 1}{3}) + 2 πn, θ = - arccos (\frac{4 k - 1}{3}) + 2 πn

Solution steps

cos (θ) = \frac{4 k - 1}{3}

Apply trig inverse properties

cos (θ) = \frac{4 k - 1}{3}

General solutions for

cos (θ) = \frac{4 k - 1}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

θ = arccos (\frac{4 k - 1}{3}) + 2 πn, θ = - arccos (\frac{4 k - 1}{3}) + 2 πn

θ = arccos (\frac{4 k - 1}{3}) + 2 πn, θ = - arccos (\frac{4 k - 1}{3}) + 2 πn

5 sin (x) - 4 = 0

tan^{2} (θ) - 2 tan (θ) - 3 = 0

cos^{3} (x) + sin^{2} (x) \cdot cos (x) = - \frac{1}{2}

cos (3 A) + sin (A) = 0

0 = 1 - sec^{2} (x)

What is the general solution for cos(θ)=(4k-1)/3 ?
The general solution for cos(θ)=(4k-1)/3 is θ=arccos((4k-1)/3)+2pin,θ=-arccos((4k-1)/3)+2pin