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Popular >

sin(10x)=sin(10(x+1))

Solution

sin (10 x) = sin (10 (x + 1))

Solution

x = - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}, x = - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

Degrees

x = - 19.64788 \dots^{\circ} + 3 6^{\circ} n, x = - 1.64788 \dots^{\circ} + 3 6^{\circ} n

Solution steps

sin (10 x) = sin (10 (x + 1))

Subtract

sin (10 (x + 1))

from both sides

sin (10 x) - sin (10 (x + 1)) = 0

Rewrite using trig identities

sin (10 x) - sin (10 (x + 1))

Use the Sum to Product identity:

sin (s) - sin (t) = 2 sin (\frac{s - t}{2}) cos (\frac{s + t}{2})

= 2 sin (\frac{10 x - 10 ( x + 1 )}{2}) cos (\frac{10 x + 10 ( x + 1 )}{2})

Simplify

2 sin (\frac{10 x - 10 ( x + 1 )}{2}) cos (\frac{10 x + 10 ( x + 1 )}{2}) : - 2 sin (5) cos (5 (2 x + 1))

2 sin (\frac{10 x - 10 ( x + 1 )}{2}) cos (\frac{10 x + 10 ( x + 1 )}{2})

\frac{10 x - 10 ( x + 1 )}{2} = - 5

\frac{10 x - 10 ( x + 1 )}{2}

Factor

10 x - 10 (x + 1) : - 10

10 x - 10 (x + 1)

Factor out common term

10

= 10 (x - (1 + x))

Expand

x - (x + 1) : - 1

x - (1 + x)

- (1 + x) : - 1 - x

- (1 + x)

Distribute parentheses

= - (1) - (x)

Apply minus-plus rules

+ (- a) = - a

= - 1 - x

= x - 1 - x

Simplify

x - 1 - x : - 1

x - 1 - x

Group like terms

= x - x - 1

Add similar elements:

x - x = 0

= - 1

= - 1

= 10 (- 1)

Refine

= - 10

= - \frac{10}{2}

Divide the numbers:

\frac{10}{2} = 5

= - 5

= 2 sin (- 5) cos (\frac{10 x + 10 ( x + 1 )}{2})

Simplify

sin (- 5) : - sin (5)

sin (- 5)

Use the following property:

sin (- x) = - sin (x)

sin (- 5) = - sin (5)

= - sin (5)

= 2 (- sin (5)) cos (\frac{10 x + 10 ( x + 1 )}{2})

\frac{10 x + 10 ( x + 1 )}{2} = 5 (2 x + 1)

\frac{10 x + 10 ( x + 1 )}{2}

Factor

10 x + 10 (x + 1) : 10 (2 x + 1)

10 x + 10 (x + 1)

Factor out common term

10

= 10 (x + 1 + x)

Refine

= 10 (2 x + 1)

= \frac{10 ( 2 x + 1 )}{2}

Divide the numbers:

\frac{10}{2} = 5

= 5 (2 x + 1)

= 2 (- sin (5)) cos (5 (2 x + 1))

Remove parentheses:

(- a) = - a

= - 2 sin (5) cos (5 (2 x + 1))

= - 2 sin (5) cos (5 (2 x + 1))

- 2 sin (5) cos (5 (2 x + 1)) = 0

Divide both sides by

- 2 sin (5)

- 2 sin (5) cos (5 (2 x + 1)) = 0

Divide both sides by

- 2 sin (5)

\frac{- 2 sin ( 5 ) cos ( 5 ( 2 x + 1 ) )}{- 2 sin ( 5 )} = \frac{0}{- 2 sin ( 5 )}

Simplify

cos (5 (2 x + 1)) = 0

cos (5 (2 x + 1)) = 0

General solutions for

cos (5 (2 x + 1)) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

5 (2 x + 1) = \frac{π}{2} + 2 πn, 5 (2 x + 1) = \frac{3 π}{2} + 2 πn

5 (2 x + 1) = \frac{π}{2} + 2 πn, 5 (2 x + 1) = \frac{3 π}{2} + 2 πn

Solve

5 (2 x + 1) = \frac{π}{2} + 2 πn : x = - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}

5 (2 x + 1) = \frac{π}{2} + 2 πn

Divide both sides by

5

5 (2 x + 1) = \frac{π}{2} + 2 πn

Divide both sides by

5

\frac{5 ( 2 x + 1 )}{5} = \frac{\frac{π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 ( 2 x + 1 )}{5} = \frac{\frac{π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 ( 2 x + 1 )}{5} : 2 x + 1

\frac{5 ( 2 x + 1 )}{5}

Divide the numbers:

\frac{5}{5} = 1

= 2 x + 1

Simplify

\frac{\frac{π}{2}}{5} + \frac{2 πn}{5} : \frac{π}{10} + \frac{2 πn}{5}

\frac{\frac{π}{2}}{5} + \frac{2 πn}{5}

\frac{\frac{π}{2}}{5} = \frac{π}{10}

\frac{\frac{π}{2}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 5}

Multiply the numbers:

2 \cdot 5 = 10

= \frac{π}{10}

= \frac{π}{10} + \frac{2 πn}{5}

2 x + 1 = \frac{π}{10} + \frac{2 πn}{5}

2 x + 1 = \frac{π}{10} + \frac{2 πn}{5}

2 x + 1 = \frac{π}{10} + \frac{2 πn}{5}

Move

1

to the right side

2 x + 1 = \frac{π}{10} + \frac{2 πn}{5}

Subtract

1

from both sides

2 x + 1 - 1 = \frac{π}{10} + \frac{2 πn}{5} - 1

Simplify

2 x = \frac{π}{10} + \frac{2 πn}{5} - 1

2 x = \frac{π}{10} + \frac{2 πn}{5} - 1

Divide both sides by

2

2 x = \frac{π}{10} + \frac{2 πn}{5} - 1

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2} : - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}

\frac{\frac{π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2}

Group like terms

= - \frac{1}{2} + \frac{\frac{π}{10}}{2} + \frac{\frac{2 πn}{5}}{2}

\frac{\frac{π}{10}}{2} = \frac{π}{20}

\frac{\frac{π}{10}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{10 \cdot 2}

Multiply the numbers:

10 \cdot 2 = 20

= \frac{π}{20}

\frac{\frac{2 πn}{5}}{2} = \frac{πn}{5}

\frac{\frac{2 πn}{5}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2 πn}{5 \cdot 2}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{2 πn}{10}

Cancel the common factor:

2

= \frac{πn}{5}

= - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}

x = - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}

x = - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}

x = - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}

Solve

5 (2 x + 1) = \frac{3 π}{2} + 2 πn : x = - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

5 (2 x + 1) = \frac{3 π}{2} + 2 πn

Divide both sides by

5

5 (2 x + 1) = \frac{3 π}{2} + 2 πn

Divide both sides by

5

\frac{5 ( 2 x + 1 )}{5} = \frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 ( 2 x + 1 )}{5} = \frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 ( 2 x + 1 )}{5} : 2 x + 1

\frac{5 ( 2 x + 1 )}{5}

Divide the numbers:

\frac{5}{5} = 1

= 2 x + 1

Simplify

\frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5} : \frac{3 π}{10} + \frac{2 πn}{5}

\frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5}

\frac{\frac{3 π}{2}}{5} = \frac{3 π}{10}

\frac{\frac{3 π}{2}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3 π}{2 \cdot 5}

Multiply the numbers:

2 \cdot 5 = 10

= \frac{3 π}{10}

= \frac{3 π}{10} + \frac{2 πn}{5}

2 x + 1 = \frac{3 π}{10} + \frac{2 πn}{5}

2 x + 1 = \frac{3 π}{10} + \frac{2 πn}{5}

2 x + 1 = \frac{3 π}{10} + \frac{2 πn}{5}

Move

1

to the right side

2 x + 1 = \frac{3 π}{10} + \frac{2 πn}{5}

Subtract

1

from both sides

2 x + 1 - 1 = \frac{3 π}{10} + \frac{2 πn}{5} - 1

Simplify

2 x = \frac{3 π}{10} + \frac{2 πn}{5} - 1

2 x = \frac{3 π}{10} + \frac{2 πn}{5} - 1

Divide both sides by

2

2 x = \frac{3 π}{10} + \frac{2 πn}{5} - 1

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{3 π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{3 π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{3 π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2} : - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

\frac{\frac{3 π}{10}}{2} + \frac{\frac{2 πn}{5}}{2} - \frac{1}{2}

Group like terms

= - \frac{1}{2} + \frac{\frac{3 π}{10}}{2} + \frac{\frac{2 πn}{5}}{2}

\frac{\frac{3 π}{10}}{2} = \frac{3 π}{20}

\frac{\frac{3 π}{10}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3 π}{10 \cdot 2}

Multiply the numbers:

10 \cdot 2 = 20

= \frac{3 π}{20}

\frac{\frac{2 πn}{5}}{2} = \frac{πn}{5}

\frac{\frac{2 πn}{5}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2 πn}{5 \cdot 2}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{2 πn}{10}

Cancel the common factor:

2

= \frac{πn}{5}

= - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

x = - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

x = - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

x = - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

x = - \frac{1}{2} + \frac{π}{20} + \frac{πn}{5}, x = - \frac{1}{2} + \frac{3 π}{20} + \frac{πn}{5}

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