What is the general solution for solvefor x,cos(x)+1=0 ?

The general solution for solvefor x,cos(x)+1=0 is x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,cos(x)+1=0

solve for

x, cos (x) + 1 = 0

x = π + 2 πn

Degrees

x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) + 1 = 0

Move

1

to the right side

cos (x) + 1 = 0

Subtract

1

from both sides

cos (x) + 1 - 1 = 0 - 1

Simplify

cos (x) = - 1

cos (x) = - 1

General solutions for

cos (x) = - 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

- 8 sin (x) = 0

sin (θ + \frac{π}{4}) = 0

2 sin^{2} (x) - 7 sin (x) + 3 = 0, 0 \leq x \leq 2 π

csc (θ) = - \frac{( 2 3 )}{3}

tan (x - 2 0^{\circ}) = tan (2 x + 10)

What is the general solution for solvefor x,cos(x)+1=0 ?
The general solution for solvefor x,cos(x)+1=0 is x=pi+2pin