What is the general solution for -arctan(t)=(4-pi)/4 ?

The general solution for -arctan(t)=(4-pi)/4 is t=-tan((4-pi)/4)

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-arctan(t)=(4-pi)/4

- arctan (t) = \frac{4 - π}{4}

t = - tan (\frac{4 - π}{4})

Solution steps

- arctan (t) = \frac{4 - π}{4}

Divide both sides by

- 1

- arctan (t) = \frac{4 - π}{4}

Divide both sides by

- 1

\frac{- arctan ( t )}{- 1} = \frac{\frac{4 - π}{4}}{- 1}

Simplify

\frac{- arctan ( t )}{- 1} = \frac{\frac{4 - π}{4}}{- 1}

Simplify

\frac{- arctan ( t )}{- 1} : arctan (t)

\frac{- arctan ( t )}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{arctan ( t )}{1}

Apply rule

\frac{a}{1} = a

= arctan (t)

Simplify

\frac{\frac{4 - π}{4}}{- 1} : - \frac{4 - π}{4}

\frac{\frac{4 - π}{4}}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{4 - π}{4}}{1}

Apply the fraction rule:

\frac{a}{1} = a

\frac{\frac{4 - π}{4}}{1} = \frac{4 - π}{4}

= - \frac{4 - π}{4}

arctan (t) = - \frac{4 - π}{4}

arctan (t) = - \frac{4 - π}{4}

arctan (t) = - \frac{4 - π}{4}

Apply trig inverse properties

arctan (t) = - \frac{4 - π}{4}

arctan (x) = a \Rightarrow x = tan (a)

t = tan (- \frac{4 - π}{4})

tan (- \frac{4 - π}{4}) = - tan (\frac{4 - π}{4})

tan (- \frac{4 - π}{4})

Use the following property:

tan (- x) = - tan (x)

tan (- \frac{4 - π}{4}) = - tan (\frac{4 - π}{4})

= - tan (\frac{4 - π}{4})

t = - tan (\frac{4 - π}{4})

t = - tan (\frac{4 - π}{4})

cos^{2} (x + 3 0^{\circ}) = \frac{1}{4}

cos (5 7^{\circ}) = sin (x)

3 cos (x) = 2 - cos (x)

2 cos^{2} (3 x) - 3 cos (3 x) = - 1, 0 \leq x \leq 2 π

x, z = y^{s i n (x)}

What is the general solution for -arctan(t)=(4-pi)/4 ?
The general solution for -arctan(t)=(4-pi)/4 is t=-tan((4-pi)/4)