What is the general solution for cos(x)=(sqrt(3))/2 ,sin(2x),-90<= x<= 0 ?

The general solution for cos(x)=(sqrt(3))/2 ,sin(2x),-90<= x<= 0 is No Solution for x\in\mathbb{R}

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cos(x)=(sqrt(3))/2 ,sin(2x),-90<= x<= 0

cos (x) = \frac{3}{2}, sin (2 x), - 9 0^{\circ} \leq x \leq 0^{\circ}

No Solution for x \in R

Solution steps

cos (x) = \frac{3}{2}, sin (2 x), - 9 0^{\circ} \leq x \leq 0^{\circ}

General solutions for

cos (x) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solutions for the range

sin (2 x)

No Solution for x \in R

sin (x) = 2 \cdot 589.594 \cdot 1 0^{- 9} \cdot 300 \cdot 1 0^{3}

sec (x) = - \frac{\frac{1}{2}}{3}

cos^{2} (θ) + \frac{2 0 ^{2} cos ( θ )}{9.81 ( 1 )} - 1 = 0

3 sin (θ) + 5 = 6

\frac{9}{73} + sin^{2} (θ) = 1

What is the general solution for cos(x)=(sqrt(3))/2 ,sin(2x),-90<= x<= 0 ?
The general solution for cos(x)=(sqrt(3))/2 ,sin(2x),-90<= x<= 0 is No Solution for x\in\mathbb{R}