What is the general solution for cos(θ)=(sqrt(7))/4 ?

The general solution for cos(θ)=(sqrt(7))/4 is θ=0.84806…+2pin,θ=2pi-0.84806…+2pin

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cos(θ)=(sqrt(7))/4

cos (θ) = \frac{7}{4}

θ = 0.84806 \dots + 2 πn, θ = 2 π - 0.84806 \dots + 2 πn

Degrees

θ = 48.59037 \dots^{\circ} + 36 0^{\circ} n, θ = 311.40962 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{7}{4}

Apply trig inverse properties

cos (θ) = \frac{7}{4}

General solutions for

cos (θ) = \frac{7}{4}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{7}{4}) + 2 πn, θ = 2 π - arccos (\frac{7}{4}) + 2 πn

θ = arccos (\frac{7}{4}) + 2 πn, θ = 2 π - arccos (\frac{7}{4}) + 2 πn

Show solutions in decimal form

θ = 0.84806 \dots + 2 πn, θ = 2 π - 0.84806 \dots + 2 πn

sin (2 θ - \frac{π}{2}) = - 1, 0 \leq θ \leq 2 π

sin (\frac{π}{11}) = sin (\frac{x π}{11})

3 + cos (4 θ) = 2 - cos (4 θ)

5 sec (θ) = 4 sec (θ) + 2

4 sec (π x) + 6 = - 2

What is the general solution for cos(θ)=(sqrt(7))/4 ?
The general solution for cos(θ)=(sqrt(7))/4 is θ=0.84806…+2pin,θ=2pi-0.84806…+2pin