What is the general solution for 0=3cos(x) ?

The general solution for 0=3cos(x) is x= pi/2+2pin,x=(3pi)/2+2pin

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0=3cos(x)

0 = 3 cos (x)

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

0 = 3 cos (x)

Switch sides

3 cos (x) = 0

Divide both sides by

3

3 cos (x) = 0

Divide both sides by

3

\frac{3 cos ( x )}{3} = \frac{0}{3}

Simplify

cos (x) = 0

cos (x) = 0

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

2 cos^{2} (x) + 3 cos (x) + 1 = 0, 0 \leq x < 2 π

tan (\frac{π}{2} - x) + tan (x) - 1 = 0

cos (1000 t) = 1

3 sin (\frac{θ}{4}) - \frac{3}{2} = 0, 0 \leq θ \leq 2 π

\frac{1 - tan ^{2} ( A )}{2 tan ( A )} = cot (A)

What is the general solution for 0=3cos(x) ?
The general solution for 0=3cos(x) is x= pi/2+2pin,x=(3pi)/2+2pin