What is the general solution for tan(x)= 1/5 ,tan(x+pi/2) ?

The general solution for tan(x)= 1/5 ,tan(x+pi/2) is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(x)= 1/5 ,tan(x+pi/2)

tan (x) = \frac{1}{5}, tan (x + \frac{π}{2})

No Solution for x \in R

Solution steps

tan (x) = \frac{1}{5}, tan (x + \frac{π}{2})

Apply trig inverse properties

tan (x) = \frac{1}{5}

General solutions for

tan (x) = \frac{1}{5}

tan (x) = a \Rightarrow x = arctan (a) + πn

x = arctan (\frac{1}{5}) + πn

x = arctan (\frac{1}{5}) + πn

Solutions for the range

tan (x + \frac{π}{2})

No Solution for x \in R

2 cos (5 x) = 0

sin (θ) = - \frac{5}{4}

2 sin^{2} (\frac{x}{2}) + cos (x) = 1 + sin (x)

5 sin^{2} (x) - 6 sin (x) cos (x) = 0

10 sin (20 t - \frac{π}{6}) = 8

What is the general solution for tan(x)= 1/5 ,tan(x+pi/2) ?
The general solution for tan(x)= 1/5 ,tan(x+pi/2) is No Solution for x\in\mathbb{R}