What is the general solution for (sin(73))/(34)=(sin(d))/(29) ?

The general solution for (sin(73))/(34)=(sin(d))/(29) is d=0.95388…+360n,d=180-0.95388…+360n

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(sin(73))/(34)=(sin(d))/(29)

\frac{sin ( 7 3 ^{\circ} )}{34} = \frac{sin ( d )}{29}

d = 0.95388 \dots + 36 0^{\circ} n, d = 18 0^{\circ} - 0.95388 \dots + 36 0^{\circ} n

Radians

d = 0.95388 \dots + 2 πn, d = π - 0.95388 \dots + 2 πn

Solution steps

\frac{sin ( 7 3 ^{\circ} )}{34} = \frac{sin ( d )}{29}

Switch sides

\frac{sin ( d )}{29} = \frac{sin ( 7 3 ^{\circ} )}{34}

Multiply both sides by

29

\frac{sin ( d )}{29} = \frac{sin ( 7 3 ^{\circ} )}{34}

Multiply both sides by

29

\frac{29 sin ( d )}{29} = \frac{29 sin ( 7 3 ^{\circ} )}{34}

Simplify

sin (d) = \frac{29 sin ( 7 3 ^{\circ} )}{34}

sin (d) = \frac{29 sin ( 7 3 ^{\circ} )}{34}

Apply trig inverse properties

sin (d) = \frac{29 sin ( 7 3 ^{\circ} )}{34}

General solutions for

sin (d) = \frac{29 sin ( 7 3 ^{\circ} )}{34}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

d = arcsin (\frac{29 sin ( 7 3 ^{\circ} )}{34}) + 36 0^{\circ} n, d = 18 0^{\circ} - arcsin (\frac{29 sin ( 7 3 ^{\circ} )}{34}) + 36 0^{\circ} n

d = arcsin (\frac{29 sin ( 7 3 ^{\circ} )}{34}) + 36 0^{\circ} n, d = 18 0^{\circ} - arcsin (\frac{29 sin ( 7 3 ^{\circ} )}{34}) + 36 0^{\circ} n

Show solutions in decimal form

d = 0.95388 \dots + 36 0^{\circ} n, d = 18 0^{\circ} - 0.95388 \dots + 36 0^{\circ} n

θ, \frac{9 0 ^{2}}{250 ( 32.2 )} = tan (θ)

sin (θ) = 2 sin (θ) cos (θ)

x, arccos (e^{- x}) = \frac{π}{3}

2 cos^{2} (4 x + 1) = 0

x, 2 sin (x) = - 1

What is the general solution for (sin(73))/(34)=(sin(d))/(29) ?
The general solution for (sin(73))/(34)=(sin(d))/(29) is d=0.95388…+360n,d=180-0.95388…+360n