What is the general solution for cos(x)=\pm 1/2 ?

The general solution for cos(x)=\pm 1/2 is No Solution for x\in\mathbb{R}

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cos(x)=\pm 1/2

cos (x) = \pm \frac{1}{2}

No Solution for x \in R

Solution steps

cos (x) = \pm \frac{1}{2}

Apply trig inverse properties

cos (x) = \pm \frac{1}{2}

General solutions for

cos (x) = \pm \frac{1}{2}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (\pm \frac{1}{2}) + 2 πn, x = - arccos (\pm \frac{1}{2}) + 2 πn

x = arccos (\pm \frac{1}{2}) + 2 πn, x = - arccos (\pm \frac{1}{2}) + 2 πn

Since the equation is undefined for:

arccos (\pm \frac{1}{2}) + 2 πn, - arccos (\pm \frac{1}{2}) + 2 πn

No Solution for x \in R

\frac{cos ( θ )}{1 + sin ( θ )} = tan (\frac{π}{4} - θ)

sin (x) = \frac{1}{4 sin ( x )}

cos (4 θ) = cos (3 θ)

\frac{- 2 3}{3} = sec (θ)

\frac{- 2 sin ( x ) - 1}{( 2 + sin ( x ) ) ^{2}} = 0

What is the general solution for cos(x)=\pm 1/2 ?
The general solution for cos(x)=\pm 1/2 is No Solution for x\in\mathbb{R}